在django中显示图像

时间:2020-03-03 08:36:59

标签: javascript python html django

我有一个Django Web应用程序,我在其中上传图像并显示一些文本。但是上传后我无法在前端显示图像。

views.py

def index(request):
    if request.method == "GET":
        return render(request, 'index.html')
    elif request.method == "POST":
        input_file = request.FILES['file']
        media_root = settings.MEDIA_ROOT
        fs = FileSystemStorage()
        filename = fs.save(input_file.name, input_file)
        uploaded_file_url = fs.url(filename)
        filepath = os.path.join(media_root, filename)
        images = segment_lines(filepath)
        extracted_text = extract()
        copy2(filepath, '/home/user/ocr/ocr/static/'+ filename)
        response = { "response" : extracted_text, "img": filename}
        return JsonResponse(response, safe=False)

index.html

<form action="" id="file-form" method="POST" enctype="multipart/form-data">
    {% csrf_token %}
    <div class="row">
        <div class="col-sm-10 col-md-10 col-lg-9">
            <div class="form-group">
               <div class="input-group">
                   <div class="input-group-prepend">
                       <span class="input-group-text" id="inputGroupFileAddon01">Upload</span>
                    </div>
                    <div class="custom-file">
                        <input type="file"  accept="image/*" name="file" class="custom-file-input" id="inputGroupFile01" aria-describedby="inputGroupFileAddon01">
                        <label class="custom-file-label" for="inputGroupFile01">Choose file</label>
                    </div>
                </div>           
            </div>            
      </div>

      <div class="col-sm-2 col-md-2 col-lg-3">
          <span class="upload-btn">
          <button type="submit" id='upload-button' class="btn btn btn-outline-dark">Extract</button>
          </span>
      </div>
     </div>
 </form>
<div class="row" style="border:none;">
      <div class="col-xs-6 mx-auto" id="img_data">
      </div>
      <div class="col-xs-6 mx-auto" id="content_data">
      </div>
</div>
<script type="text/javascript">
    var form = document.getElementById('file-form');
    var fileSelect = document.getElementById('inputGroupFile01');
    var uploadButton = document.getElementById('upload-button');

    form.onsubmit = function(event) {
      event.preventDefault();
      uploadButton.innerHTML = 'Processing ...';
      var file = fileSelect.files[0];
      var formData = new FormData();
      formData.append('file', file, file.name);
      formData.append('csrfmiddlewaretoken', '{{ csrf_token }}');

      var xhr = new XMLHttpRequest();
      xhr.open('POST', 'http://127.0.0.1:8000', true);

      xhr.onload = function () {

        if (xhr.status === 200) {
          uploadButton.innerHTML = 'Extract';
          var data = JSON.parse(xhr.responseText);
          var follow_up = data['response'];
          var corrected = data["correct_response"]
          var demoid = document.getElementById("content_data");

          var btnid = document.getElementById('btn-data')
          var imgid = document.getElementById('img_data')
          var img_path = data["img"]
          var final_content = follow_up;
          demoid.innerHTML = '<h3>Extracted Text</h3><p id="rcorners3">' + final_content + '</p>'
</script>

如何在此处显示上传的图片,我对javascript的了解很少,因此如果有人可以帮助我!

到目前为止,我尝试的是传递图像路径URL,并使用{%static%}尝试显示如下图像

imgid.innerHTML = '<h3>Your Image</h3><img class="id-of-img-tag" src="" alt="img" style="width:300px;height:300px;margin-right:15px;">'
document.querySelector(".id-of-img-tag").src = "{% static " + img_path + " %}";

2 个答案:

答案 0 :(得分:1)

如果图像的路径有效,则应使用new Image()构造函数创建图像。这类似于执行document.createElement('img')创建图像。构造函数返回一个HTMLImageElement实例,该实例基本上是与<img>元素等效的JavaScript。

为确保正确加载,请监听图像上的load事件。这样,当图像下载完成后,您可以将其添加到页面中。

然后设置图像的src属性(还将设置属性)以开始从静态文件夹下载图像。

...
var btnid = document.getElementById('btn-data')
var imgid = document.getElementById('img_data')
var img_path = data["img"]

var image = new Image();
image.addEventListener('load', function() {
  var title = document.createElement('h3');
  title.textContent = 'Your image';
  image.className = 'id-of-img-tag';
  image.alt = 'img';
  image.style.width = '300px';
  image.style.height = '300px';
  image.style.marginRight = '15px';
  imgid.append(title, image);
}, {once: true});
image.src = img_path;

var final_content = follow_up;
demoid.innerHTML = '<h3>Extracted Text</h3><p id="rcorners3">' + final_content + '</p>'

答案 1 :(得分:0)

您可能需要使用fs.url()来重新构建已保存图像的URL。

此外,如评论中所述,segment_lines()应该真正返回extract_text()将使用的文件名列表。否则,如果/当您使用单个临时文件夹时,并发请求将造成严重破坏。

from django.core.files.storage import FileSystemStorage
from django.http import JsonResponse


def extract_text(input_paths):
    # ... Do some magic using the input paths ...
    return 'hello'


def segment_lines(image_path):
    return [
        # ... file paths for segmented result...
    ]


def handle(request):
    input_file = request.FILES['file']
    fs = FileSystemStorage()
    filename = fs.save(input_file.name, input_file)
    images = segment_lines(fs.path(filename))
    extracted_text = extract_text(images)
    response = {"response": extracted_text, "img_url": fs.url(filename)}
    return JsonResponse(response)

然后,使用fetch()和表单数据来简化HTML版本:

<form action="" id="file-form" method="POST" enctype="multipart/form-data">
    {% csrf_token %}
    <input type="file" accept="image/*" name="file" id="inputGroupFile01" aria-describedby="inputGroupFileAddon01">
    <button type="submit" id='upload-button' class="btn btn btn-outline-dark">Extract</button>
</form>
<div id="content_data"></div>
<script type="text/javascript">
  var form = document.getElementById('file-form');
  var uploadButton = document.getElementById('upload-button');

  form.onsubmit = function (event) {
    event.preventDefault();
    uploadButton.innerHTML = 'Processing ...';
    fetch('/', {body: new FormData(form)})
      .then(resp => resp.json())
      .then(data => {
        console.log(data);
        const demoid = document.getElementById('content_data');
        demoid.innerText = JSON.stringify(data);
        // or to show the image:
        // demoid.innerHTML = `<img src="${data.img_url}"/>`;
      });
  };
</script>

肯定有一些我想念的东西。

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