Question

我在下面有这个结构，我想遍历层次结构而不丢失任何对象。

{
  "countries": [
    {
      "name": "Denmark",
      "id": "APA1",
      "children": [
        {
          "name": "Zealand",
          "id": "APA1.1",
          "parentId": "APA1",
          "children": [
            {
              "name": "Copenhagen",
              "id": "APA1.1.1",
              "parentId": "APA1.1",
              "children": [
                {
                  "name": "Dublin",
                  "id": "ANA1",
                  "parentId": "APA1.1.1.1",
                  "hostNames": [
                    {
                      "ip": "20.190.129.1"
                    },
                    {
                      "ip": "20.190.129.2"
                    }
                  ]
                }
              ]
            }
          ]
        },
        {
          "name": "Jutland",
          "id": "APA1.2",
          "parentId": "APA1",
          "children": [
            {
              "name": "Nordjylland",
              "id": "APA1.2.1",
              "parentId": "APA1.2",
              "children": [
                {
                  "name": "Aalborg",
                  "id": "APA1.2.1.1",
                  "parentId": "APA1.2.1",
                  "children": [
                    {
                      "name": "Risskov",
                      "id": "ANA3",
                      "parentId": "APA1.2.1.1",
                      "hostNames": [
                        {
                          "ip": "40.101.81.146"
                        }
                      ]
                    },
                    {
                      "name": "Brabrand",
                      "id": "ANA4",
                      "parentId": "APA1.2.1.1",
                      "hostNames": [
                        {
                          "ip": "43.203.94.182"
                        }
                      ]
                    }
                  ]
                }
              ]
            }
          ]
        }
      ]
    }
  ]
}

我想遍历层次结构的原因是我想将其变成一个平面结构。所以从本质上讲，我要把每个对象移到另一个具有所需结构的数组中。我只想知道如何接触孩子。

所需结果：

"applicationGroups": [
    {
        "id" : "APA1",
        "name": "Denmark",
    },
    {
        "name": "Zealand",
        "id": "APA1.1",
        "parentId": "APA1"
    },
    {
        "name": "Copenhagen",
        "id": "APA1.1.1",
        "parentId": "APA1.1"
    },
    {
        "name": "Dublin",
        "id": "ANA1",
        "parentId": "APA1.1.1.1"
    },
    {
        "name": "Jutland",
        "id": "APA1.2",
        "parentId": "APA1"
    },
    {
        "name": "Nordjylland",
        "id": "APA1.2.1",
        "parentId": "APA1.2"
    },
    {
        "name": "Aalborg",
        "id": "APA1.2.1.1",
        "parentId": "APA1.2.1"
    },
    {
        "name": "Risskov",
        "id": "ANA3",
        "parentId": "APA1.2.1.1"
    },
    {
        "name": "Brabrand",
        "id": "ANA4",
        "parentId": "APA1.2.1.1"
    }
]

我对JavaScript有点陌生，我真的不知道从哪里开始，但是我给出的这个示例与我正在研究的实际示例并不相同，所以我只想了解原理所以我可以在自己的实际代码中实现它。

Answer 1

您可以结合使用Array.flat()方法和this answer来递归地展平对象。使用递归函数是完成此任务的更快方法。

Answer 2

要获得平面结构，可以使用reduce方法来创建递归函数。

const data = {"countries":[{"name":"Denmark","id":"APA1","children":[{"name":"Zealand","id":"APA1.1","parentId":"APA1","children":[{"name":"Copenhagen","id":"APA1.1.1","parentId":"APA1.1","children":[{"name":"Dublin","id":"ANA1","parentId":"APA1.1.1.1","hostNames":[{"ip":"20.190.129.1"},{"ip":"20.190.129.2"}]}]}]},{"name":"Jutland","id":"APA1.2","parentId":"APA1","children":[{"name":"Nordjylland","id":"APA1.2.1","parentId":"APA1.2","children":[{"name":"Aalborg","id":"APA1.2.1.1","parentId":"APA1.2.1","children":[{"name":"Risskov","id":"ANA3","parentId":"APA1.2.1.1","hostNames":[{"ip":"40.101.81.146"}]},{"name":"Brabrand","id":"ANA4","parentId":"APA1.2.1.1","hostNames":[{"ip":"43.203.94.182"}]}]}]}]}]}]}

function flat(data) {
  return data.reduce((r, { children, ...rest }) => {
    if (children) r.push(...flat(children))
    r.push(rest)
    return r;
  }, [])
}

const result = flat(data.countries)
console.log(result)

Answer 3

对于扁平回调的递归调用，您可以采用flatMap方法。

const
    flat = ({ hostNames, children = [], ...o }) => [o, ...children.flatMap(flat)],
    data = { countries: [{ name: "Denmark", id: "APA1", children: [{ name: "Zealand", id: "APA1.1", parentId: "APA1", children: [{ name: "Copenhagen", id: "APA1.1.1", parentId: "APA1.1", children: [{ name: "Dublin", id: "ANA1", parentId: "APA1.1.1.1", hostNames: [{ ip: "20.190.129.1" }, { ip: "20.190.129.2" }] }] }] }, { name: "Jutland", id: "APA1.2", parentId: "APA1", children: [{ name: "Nordjylland", id: "APA1.2.1", parentId: "APA1.2", children: [{ name: "Aalborg", id: "APA1.2.1.1", parentId: "APA1.2.1", children: [{ name: "Risskov", id: "ANA3", parentId: "APA1.2.1.1", hostNames: [{ ip: "40.101.81.146" }] }, { name: "Brabrand", id: "ANA4", parentId: "APA1.2.1.1", hostNames: [{ ip: "43.203.94.182" }] }] }] }] }] }] },
    result = data.countries.flatMap(flat);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

如何遍历嵌套数组？

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