Question

如何通过unixstamp获得最近24小时内不超过900秒的行？谢谢

CREATE TABLE `users` (
  `id` int(10) UNSIGNED NOT NULL,                     // User ID
  `regdate` int(10) UNSIGNED NOT NULL DEFAULT '0',    // Registration date in UNIX timestamp 
  `lastactive` int(10) UNSIGNED NOT NULL DEFAULT '0', // Last active date in UNIX timestamp 
  `lastvisit` int(10) UNSIGNED NOT NULL DEFAULT '0',  // Last visit date in UNIX timestamp
  `lastpost` int(10) UNSIGNED NOT NULL DEFAULT '0'    // Last post date in UNIX timestamp 
) ENGINE=MyISAM DEFAULT CHARSET=utf8;

INSERT INTO `users` (`id`, `regdate`, `lastactive`, `lastvisit`, `lastpost`) VALUES (13, 1569915390, 1583430726, 1583425902, 1583378778);

/*
* regdate = 1569915390 = Tuesday, October 1, 2019 7:36:30 AM
* lastactive= 1583430726 = Thursday, March 5, 2020 5:52:06 PM
* lastvisit = 1583425902 = Thursday, March 5, 2020 4:31:42 PM
* lastpost = 1583378778 = Thursday, March 5, 2020 3:26:18 AM
* 
* 1. On connection and other activity, the lastactive is updated with time ()
* 
* 2. If the session cookie is older than 900 seconds then lastvisit is updated from lastactive
* 
* 3. When disconnected, lastvisit is updated from lastactive
*/

这是我的查询内容：

SELECT id
FROM users
WHERE lastvisit > (NOW() - INTERVAL 24 HOUR) AND (NOW() - lastactive < 900)

编辑：我想我是在@tadman

的帮助下找到的

SELECT *
FROM users
WHERE lastvisit < (NOW() - INTERVAL 24 HOUR) AND lastactive < (NOW() - INTERVAL 900 SECOND)

Answer 1

这是解决方案：

SELECT *
FROM users
WHERE lastvisit < (NOW() - INTERVAL 24 HOUR) AND lastactive < (NOW() - INTERVAL 900 SECOND)

unixstamp如何获得最近24小时内不超过900秒的行

1 个答案: