我有一些json代码,里面有多个对象,如下:
这些是对象内的值:
这是json代码:
[{"pk_records_id":"34","record_artist":"Bouncing Souls","record_title":"How I Spent My Summer Vacation","record_added_date":"2011-05-05 17:36:34","record_category":"punkrock","record_price":"11.00","record_cover_link":"img\/Bouncing Souls-How I Spent My Summer Vacation.jpg","record_amount_sold":null,"record_amount_stock":"400","record_description":"A great follow-up to Hopeless Romantic"},{"pk_records_id":"4","record_artist":"Descendents","record_title":"Everything Sucks","record_added_date":"2011-03-11 00:00:00","record_category":"punkrock","record_price":"12.00","record_cover_link":"img\/descendents_everything_sucks.jpg","record_amount_sold":"3124","record_amount_stock":null,"record_description":null}]
这是我尝试使用的代码,因此我可以检索值(显然):
success: function(obj_records){
$.each(obj_records, function(index, value) {
alert(obj_records.index.pk_records_id);
});
}
但这不起作用。如何检索数据?
编辑:
如果我使用此代码,我会在json代码中为每个字符获取一个数组。
$.each(obj_records, function(index, value) {
alert(index + " : " + value);
});
答案 0 :(得分:2)
尝试
for (var i=0; i<json.length; i++) {
alert("JSON Data: " + json[i].pk_records_id);
// you need to write each key name here
}
答案 1 :(得分:1)
从它的外观来看,你正在错误地访问结果。
尝试:
success: function(obj_records){
$.each(obj_records, function(index, value) {
alert(value.pk_records_id);
});
}
答案 2 :(得分:0)
我不确定(不是在测试它的地方),但我认为你想要:
success: function(obj_records){
$.each(obj_records, function(index, value) {
alert(value.pk_records_id);
});
}
答案 3 :(得分:0)
我相信你想要的是:
success: function(obj_records){
$.each(obj_records, function(index, value) {
alert(value.pk_records_id);
});
}
函数头中的value
参数是您要循环的obj_records
数组的单个对象。