Question

我正在使用ASP Net Core 2.2

我将这个动态对象序列化

var stuff1 = new
{
    Name = "John",
    Surname = "Smith",
    Addresses = new[] {
new { City = "New York", State = "NY"},
new { City = "Milano", State = "IT" }
};
var stuff1Serialized = JsonConvert.SerializeObject(stuff1)

这是序列化的对象：

{"Name":"John","Surname":"Smith"}

现在，我得到了这个字符串，并对其进行了反序列化

dynamic stuff1Deserialized = JsonConvert.DeserializeObject(stuff1Serialized);

我希望sutff1和stuff1Deseralized具有相同的结构，但是它们是不同的，为什么？

在立即窗口中：

stuff1.name
"Jhon"

stuff1Deserialized.Name
{John}
    First: '((Newtonsoft.Json.Linq.JToken)stuff1Deserialized.Name).First' threw an exception of type 'System.InvalidOperationException'
    HasValues: false
    Last: '((Newtonsoft.Json.Linq.JToken)stuff1Deserialized.Name).Last' threw an exception of type 'System.InvalidOperationException'
    Next: null
    Parent: {"Name": "John"}
    Path: "Name"
    Previous: null
    Root: {{
  "Name": "John",
  "Surname": "Smith"
}}
    Type: String
    Value: "John"
    Results View: Expanding the Results View will enumerate the IEnumerable

我通过简单的DotLiquid模板使用该对象：

Hello {{Name}} {{Surname}}. Number of Addresses: {{Addresses.size}} - {{Addresses[0].City}} - {{Addresses[1].City}}

有了stuff1对象，我得到了预期的结果：

Hello John Smith. Number of Addresses: 2 - New York - Milano

使用stuff1Deserialized对象，我得到了以下结果：

Hello John Smith. Number of Addresses: 2 - -

Answer 1

根据评论更新

我找到了一种方法：

1-对象动态样本：

dynamic dynamicStuff = new
{
    Name = "John",
    Surname = "Smith",
    Obj = new { City = "New York", State = "NY" },// i add this to test object
    Addresses = new[]
    {
        new { City = "New York", State = "NY"},
        new { City = "Milano", State = "IT" }
    }
};

2-序列化和反序列化以构建动态对象：

dynamic dynamicStuffDeSerialized = JsonConvert.DeserializeObject(JsonConvert.SerializeObject(dynamicStuff));

3-将dynamic转换为JObject，将Dictionary对象转换为JObject，并建立Dictionary的{string，object}，

Dictionary<string, object> keyValuePairs = ConvertJObject(JObject.FromObject(dynamicStuffDeSerialized));

private static Dictionary<string, object> ConvertJObject(JObject jObject)
{
    Dictionary<string, object> keyValuePairs = new Dictionary<string, object>();
    foreach (var property in jObject)
    {
        if (property.Value.Type == JTokenType.Array)
            keyValuePairs.Add(property.Key, ConvertJArray(property.Value.Select(o=>(JObject)o)));

        else if (property.Value.Type == JTokenType.Object)
            keyValuePairs.Add(property.Key, ConvertJObject((JObject)property.Value));

        else
            keyValuePairs.Add(property.Key, property.Value.ToString());
    }

    return keyValuePairs;
}

private static List<Dictionary<string, object>> ConvertJArray(IEnumerable<JObject> jObjects)
{
    return jObjects.Select(o => ConvertJObject(o)).ToList();
}

请注意，您可以使用ToObject将JObject转换为Dictionary，但是它只是转换简单值而不是对象或数组，例如：

JObject jObject = JObject.FromObject(dynamicStuffDeSerialized);
Dictionary<string, object> dict = jObject.ToObject<Dictionary<string, object>>();

4-使用Hash.FromDictionary而不是Hash.FromAnonymousObject：

Template templatedynamicStuff = Template.Parse("Hello {{Name}} {{Surname}} City in Object {{Obj.City}}. Number of Addresses: {{Addresses.size}} - {{Addresses[0].City}} - {{Addresses[1].City}}");
string result = templatedynamicStuff.Render(Hash.FromDictionary(keyValuePairs));

请注意，我通过添加template来更改了City in Object {{Obj.City}}

5-测试

Console.WriteLine(result);

6-结果：

Hello John Smith City in Object New York. Number of Addresses: 2 - New York - Milano

旧答案

根据 newtonsoft 文档，您可以使用DeserializeAnonymousType代替DeserializeObject来进行反序列化匿名对象。但是DeserializeAnonymousType需要definition的 Anonymous 类型才能获得相同的 object 。

类似于以下代码：

var stuff1 = new
{
    Name = "John",
    Surname = "Smith"
};

var stuff1Serialized = JsonConvert.SerializeObject(stuff1);

var definition = new { Name = "", Surname = "" };
dynamic stuff1Deserialized = JsonConvert.DeserializeAnonymousType(stuff1Serialized, definition);

根据评论更新

您可以使用JObject或ExpandoObject来获取属性名称和值，例如以下代码：

dynamic stuff1 = new
{
    Name = "John",
    Surname = "Smith"
};

var stuff1Serialized = JsonConvert.SerializeObject(stuff1);

dynamic stuff1DeSerialized1 = JsonConvert.DeserializeObject(stuff1Serialized);

foreach (JProperty property in JObject.FromObject(stuff1DeSerialized1))
{
    Console.WriteLine($"Key:{property.Name}, Value:{property.Value}");
}

ExpandoObject stuff1DeSerialized2 = JsonConvert.DeserializeObject<ExpandoObject>(stuff1Serialized, new ExpandoObjectConverter());

foreach(KeyValuePair<string, object> keyValue in stuff1DeSerialized2.ToList())
{
    Console.WriteLine($"Key:{keyValue.Key}, Value:{keyValue.Value}");
}

我希望找到其他解决方案并与您分享。

反序列化的对象，而不是原始序列化的对象

1 个答案: