想法是提取椭圆形的盘子。
我尝试了OpenCV的T
方法,但仅适用于完美圆。
我还尝试了balanceC.setCellFactory(c -> new TableCell<>() {
@Override
protected void updateItem(Double balance, boolean empty) {
super.updateItem(balance, empty);
if (balance == null || empty) {
setText(null);
} else {
setText(String.format("%.2f", balance.doubleValue());
}
}
});
中的HoughCircles
方法,但是它花费的时间太长,或者我以错误的方式实现了该方法。
使用OpenCV模块可以检测椭圆形状吗?
还有哪些其他解决方案?
答案 0 :(得分:0)
提取印版的主键是使用cv2.adaptiveThreshold,但还有几个阶段:
按形状查找椭圆的健壮性要差得多...
这是代码:
import numpy as np
import cv2
import imutils
img = cv2.imread('food_plate.jpg')
# Convert to Grayscale
gray = cv2.cvtColor(img, cv2.COLOR_BGR2GRAY)
# Apply adaptive threshold with gaussian size 51x51
thresh_gray = cv2.adaptiveThreshold(gray, 255, adaptiveMethod=cv2.ADAPTIVE_THRESH_GAUSSIAN_C, thresholdType=cv2.THRESH_BINARY, blockSize=51, C=0)
#cv2.imwrite('thresh_gray.png', thresh_gray)
# Find connected components (clusters)
nlabel,labels,stats,centroids = cv2.connectedComponentsWithStats(thresh_gray, connectivity=8)
# Find second largest cluster (the cluster is the background):
max_size = np.max(stats[1:, cv2.CC_STAT_AREA])
max_size_idx = np.where(stats[:, cv2.CC_STAT_AREA] == max_size)[0][0]
mask = np.zeros_like(thresh_gray)
# Draw the cluster on mask
mask[labels == max_size_idx] = 255
# Use "open" morphological operation for removing some artifacts
mask = cv2.morphologyEx(mask, cv2.MORPH_OPEN, cv2.getStructuringElement(cv2.MORPH_ELLIPSE, (5,5)))
#cv2.imwrite('mask.png', mask)
# Fill the plate with white pixels
cv2.floodFill(mask, None, tuple(centroids[max_size_idx].astype(int)), newVal=255, loDiff=1, upDiff=1)
#cv2.imwrite('mask.png', mask)
# Find contours, and get the contour with maximum area
cnts = cv2.findContours(mask, cv2.RETR_EXTERNAL, cv2.CHAIN_APPROX_NONE)
cnts = imutils.grab_contours(cnts)
c = max(cnts, key=cv2.contourArea)
# Draw contours with maximum size on new mask
mask2 = np.zeros_like(mask)
cv2.drawContours(mask2, [c], -1, 255, -1)
#cv2.imwrite('mask2.png', mask2)
img[(mask2==0)] = 0
# Save result
cv2.imwrite('img.jpg', img)