Question

我有一个字典mydict，其中包含一些文件名作为键，并在其中包含文本作为值。

我正在从每个文件中的文本中提取单词列表。单词存储在列表mywords中。

我尝试了以下方法。

mydict = {'File1': 'some text. \n Foo extract this. \n Bar extract this', 
'File2': 'more text. \n Bar extract this too.'}
mywords = ['Foo', 'Bar']
mylist= []
for k,v in mydict.items():
        for word in mywords:
            extracted = (re.findall('^ ' + word + ".*", v, flags=re.IGNORECASE|re.MULTILINE))
            mylist.append(extracted[:1])

这给了我

[[' Foo extract this. '],
 [' Bar extract this'],
 [],
 [' Bar extract this too.']]

但是，我希望输出每次在文件中搜索一个单词时，输出都有2个嵌套列表（每个文件），而不是一个单独的列表。

所需的输出：

[[' Foo extract this. '], [' Bar extract this']],
 [[], [' Bar extract this too.']]

Answer 1

您可能想尝试创建子列表并将其附加到列表中。这是一个可能的解决方案：

mydict = {'File1': 'some text. \n Foo extract this. \n Bar extract this', 
'File2': 'more text. \n Bar extract this too.'}
mywords = ['Foo', 'Bar']
mylist= []
for k,v in mydict.items():
    sublist = []
    for word in mywords:
        extracted = (re.findall('^ ' + word + ".*", v, flags=re.IGNORECASE|re.MULTILINE))
        sublist.append(extracted[:1])
    mylist.append(sublist)

这将输出：[[[' Foo extract this. '], [' Bar extract this']], [[], [' Bar extract this too.']]]

如果您希望字符串不包含周围的列表，请仅在有结果的情况下插入第一个结果：

import re

mydict = {'File1': 'some text. \n Foo extract this. \n Bar extract this', 
'File2': 'more text. \n Bar extract this too.'}
mywords = ['Foo', 'Bar']
mylist= []
for k,v in mydict.items():
    sublist = []
    for word in mywords:
        extracted = (re.findall('^ ' + word + ".*", v, flags=re.IGNORECASE|re.MULTILINE))
        if extracted: # Checks if there is at least one element in the list
            sublist.append(extracted[0])
    mylist.append(sublist)

这将输出：[[' Foo extract this. ', ' Bar extract this'], [' Bar extract this too.']]

如果您希望能够从每个文件中获得多个结果，则可以执行以下操作（请注意，我在第二个文件中放置了Foo的另一个匹配项：

import re

mydict = {'File1': 'some text. \n Foo extract this. \n Bar extract this', 
'File2': 'more text. \n Bar extract this too. \n Bar extract this one as well'}
mywords = ['Foo', 'Bar']
mylist= []
for k,v in mydict.items():
    sublist = []
    for word in mywords:
        extracted = (re.findall('^ ' + word + ".*", v, flags=re.IGNORECASE|re.MULTILINE))
        if extracted:
            sublist += extracted
    mylist.append(sublist)

这将输出：[[' Foo extract this. ', ' Bar extract this'], [' Bar extract this too. ', ' Bar extract this one as well']]

Python-遍历列表和字典以获得嵌套列表输出

1 个答案: