如何与常规查询一起使用yii2查询

时间:2020-04-02 14:24:39

标签: php mysql yii2

我的项目中有一个yii2查询,例如

$query=Car::find()
      ->andFilterWhere(['in','make_id',array_filter(explode(',', $this->makes))])
            ->andFilterWhere(['in','model_id',array_filter(explode(',', $this->models))])
            ->andFilterWhere(['>=', 'price', $this->price_start])
            ->andFilterWhere(['<=', 'price', $this->price_end])
            ->andFilterWhere(['>=',  ModelYear::tableName().'.year', $this->year_start])
            ->andFilterWhere(['<=',  ModelYear::tableName().'.year', $this->year_end])
            ->andFilterWhere(['>=', 'kilometer', $this->km_start])
            ->andFilterWhere(['<=', 'kilometer', $this->km_end])
            ->andFilterWhere(['like', 'title', $this->title])

我也有另一个查询,例如

$command = $connection->createCommand("select A.id,A.make_eng,Count(B.make_id) 
from tbl_car_makes A,(**Can i use the first $query here**) as B where A.id=B.make_id group by A.id,A.make_eng");
$data = $command->queryAll();

如何在指定位置的第二个查询中使用第一个查询

1 个答案:

答案 0 :(得分:0)

您有两种选择方法。

1)也许更好的选择是对第二个查询也使用查询生成器。

$query2 = (new \yii\db\Query())
    ->select(['A.id', 'A.make_eng', 'COUNT(B.make_id)')
    ->from(['A' => 'tbl_car_makes', 'B' => $query])
    ->where('A.id = B.make_id')
    ->groupBy(['A.id', 'A.make_eng']);
$data = $query2->all();

2)另一个选择是将第一个查询转换为SQL字符串。这种方法的问题在于您将不得不处理参数。

$queryCommand = $query->createCommand();
$querySql = $queryCommand->getSql();

$command = $connection->createCommand(
    "select A.id,A.make_eng,Count(B.make_id) from tbl_car_makes A,($querySql) as B where A.id=B.make_id group by A.id,A.make_eng",
    $queryCommand->params
);
$data = $command->queryAll();
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