我正在开发vue
应用程序,其中有用于驾驶执照的组件。
我有以下内容:
data() {
return {
custom_licenses: [],
basic_licenses: []
}
}
在我的方法中,我有这个:
regular_licenses() {
this.$store.dispatch("license/read").then(response => {
response.licenses.map((license, key) => {
// PUSH LICENSES WITH TYPE 'BASIC' TO this.basic_licenses
// PUSH LICENSES WITH TYPE 'CUSTOM' TO this.custom_licenses
});
});
},
在我的created()中,我有这个:
created() {
this.regular_licenses()
}
我的调度响应,返回以下内容:
licenses:
[
{
id: 1,
type: 'basic',
name: 'AMa'
},
{
id: 2,
type: 'basic',
name: 'A2'
},
{
id: 3,
type: 'basic',
name: 'C'
},
{
id: 4,
type: 'custom',
name: 'C1'
},
{
id: 5,
type: 'custom',
name: 'D'
},
and so on...
]
现在,我想遍历数组,并根据custom_licenses
属性将其分离或推入basic_licenses
和type
中,我该如何实现?
答案 0 :(得分:1)
尝试一下
regular_licenses() {
this.$store.dispatch("license/read").then(response => {
response.licenses.map((license, key) => {
switch (license.type)
case 'basic':
this.basic_licenses.push({ ...license });
break;
case 'custom':
this.custom_licenses.push({ ...license });
break;
});
});
},
答案 1 :(得分:0)
更新您的代码块:
response.licenses.map((license, key) => {
// PUSH LICENSES WITH TYPE 'BASIC' TO this.basic_licenses
if(license['type'] == 'basic') {
//deep clone
let tmpLicense = JSON.parse(JSON.stringify(license));
basic_licenses.push(tmpLicense);
} else if(license['type'] == 'custom') {
// PUSH LICENSES WITH TYPE 'CUSTOM' TO this.custom_licenses
//deep clone
let tmpLicense = JSON.parse(JSON.stringify(license));
custom_licenses.push(tmpLicense);
}
});