Question

我有类似的字符串

String stringUrl = ["url1", "url2", "url3"];

现在我删除了方括号

 String urls = stringUrl.replace("[","").replace("]","");

现在我把刺劈开了

String[] urlsArray = urls.split(",");

现在我写这段代码

for (String url : urlsArray) {
                    holder.recyclerViewHomeWorkImages.setVisibility(View.VISIBLE);
                    holder.imgButtonDownload.setVisibility(View.VISIBLE);
                    imagesList.add(new ImageHomeworkModel(url, "Name"));

                }

现在在图像作业适配器中，我写这个

 ImageHomeworkModel product = imagesList.get(position);    
 Picasso.with(context).load(product.getUrls()).into(holder.imgSetData);

现在的问题是毕加索仅加载拆分字符串的第一个网址，请帮助我快速找到解决方法

Answer 1

我正在做的错误是我只发送数组的最后一个索引现在，我将所有st一一发送

 for (i = 0; i < urlsArray.length; i++) {
                    holder.recyclerViewHomeWorkImages.setVisibility(View.VISIBLE);
                    holder.imgButtonDownload.setVisibility(View.VISIBLE);
                    imagesList.add(new ImageHomeworkModel(urlsArray[i], fileName));
                }

毕加索未加载拆分的网址

1 个答案: