我正在使用这样的行,以便将变量a分配给数组,并且效果很好
.rating-slider__inner-container {
position: relative;
padding-top: 100px;
}
.rating-slider__input {
-webkit-appearance: none;
width: 100%;
height: 5px;
background: $form-gray;
&:focus {
outline: none;
}
}
.rating-slider__input::-webkit-slider-thumb {
-webkit-appearance: none;
background: transparent;
border-color: transparent;
height: 20px;
width: 20px;
margin-top: -8px;
cursor: pointer;
}
.rating-slider__input::-moz-range-thumb {
background: transparent;
border-color: transparent;
height: 20px;
width: 20px;
cursor: pointer;
}
.rating-slider__input::-moz-focus-outer {
border: 0;
}
.rating-slider__thumb {
display: flex;
flex-direction: column;
align-items: center;
position: absolute;
top: 50px;
left: -10px;
font-size: $text-3xl;
pointer-events: none;
}
.rating-slider__value {
color: $brand-primary;
font-size: $text-lg;
}
.rating-slider__range-labels-container {
display: flex;
justify-content: space-between;
}
现在我将其存储在字符串中
a = [{"From","To";1,2;2.5,3.5;3.5,5;5.7,7}]
如何从字符串本身返回数组?我尝试使用评估,但这会引发错误
s = "[{""From"",""To"";1,2;2.5,3.5;3.5,5;5.7,7}]"
a = Evaluate(s)
答案 0 :(得分:0)
我可以弄清楚
s = "[{""From"",""To"";1,2;2.5,3.5;3.5,5;5.7,7}]"
a = Evaluate(Replace(Replace(s, "[", ""), "]", ""))
但是我欢迎更多的想法和建议。