我有这个XML：
<?xml version="1.0" encoding="utf-8" ?>
<pages>
<page id="1" bbox="0.000,0.000,462.047,680.315" rotate="0">
<textbox id="0" bbox="191.745,592.218,249.042,603.578">
<textline bbox="191.745,592.218,249.042,603.578">
<text font="NUMPTY+ImprintMTnum" bbox="191.745,592.218,199.339,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">A</text>
<text font="NUMPTY+ImprintMTnum" bbox="199.227,592.218,205.657,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">P</text>
<text font="NUMPTY+ImprintMTnum" bbox="205.545,592.218,211.975,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">P</text>
<text font="NUMPTY+ImprintMTnum" bbox="211.023,592.218,218.617,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">A</text>
<text font="NUMPTY+ImprintMTnum" bbox="218.515,592.218,226.109,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">R</text>
<text font="NUMPTY+ImprintMTnum" bbox="226.008,592.218,233.602,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">A</text>
<text font="NUMPTY+ImprintMTnum" bbox="232.812,592.218,240.932,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">T</text>
<text font="NUMPTY+ImprintMTnum" bbox="240.922,592.218,249.042,603.578" colourspace="DeviceGray" ncolour="0" size="11.360">O</text>
</textline>
</textbox>
<textbox id="1" bbox="44.614,554.008,58.101,564.246">
<textline bbox="44.614,554.008,58.101,564.246">
<text font="NUMPTY+ImprintMTnum" bbox="44.614,554.008,49.369,564.246" colourspace="DeviceGray" ncolour="0" size="10.238">2</text>
<text font="NUMPTY+ImprintMTnum" bbox="49.268,554.008,54.022,564.246" colourspace="DeviceGray" ncolour="0" size="10.238">4</text>
<text font="NUMPTY+ImprintMTnum" bbox="53.922,554.008,58.101,564.246" colourspace="DeviceGray" ncolour="0" size="10.238">a</text>
</textline>
</textbox>
<textbox id="2" bbox="43.563,475.008,58.117,485.246">
<textline bbox="43.563,475.008,58.117,485.246">
<text font="NUMPTY+ImprintMTnum" bbox="43.563,475.008,48.317,485.246" colourspace="DeviceGray" ncolour="0" size="10.238">2</text>
<text font="NUMPTY+ImprintMTnum" bbox="48.226,475.008,52.980,485.246" colourspace="DeviceGray" ncolour="0" size="10.238">4</text>
<text font="NUMPTY+ImprintMTnum" bbox="52.889,475.008,58.117,485.246" colourspace="DeviceGray" ncolour="0" size="10.238">b</text>
</textline>
</textbox>
</page>
</pages>
虽然更长，但是结构相同。
我想在每次指定一定距离（<newline>属性的第一个数字与第一个数字和第一个数字之间）之间插入一个bbox 父标签。下一个bbox属性）。我希望仅在需要打开另一个标签时才关闭标签。像这样：
<newline>
<text tags>[...]</text tags>
</newline>
<newline>
<text tags>[...]</text tags]
</newline>
因此，换行符会包装文本标签。我尝试使用我的代码，但输出不起作用。我的代码如下：
import lxml.etree as etree
from lxml.builder import E
parser = etree.XMLParser(remove_blank_text=True)
tree = etree.parse('fe3.xml', parser)
root = tree.getroot()
def removeByIdx(parent, idx):
currElem = parent[idx] # The indicated element
parent.remove(currElem) # Remove it from the parent
return currElem # Return the index and element
def wrap(line, idxList):
if len(idxList) == 0:
return # No elements to wrap
# Take the first element from the original location
idx = idxList.pop(0) # Index of the first element
elem = removeByIdx(line, idx) # The indicated element
# Create "newline" element with "elem" inside
nElem = E.newline(elem)
line.insert(idx, nElem) # Put it in place of "elem"
while len(idxList) > 0: # Process the rest of index list
# Value not used, but must be removed
idxList.pop(0)
# Remove the current element from the original location
currElem = removeByIdx(line, idx + 1)
nElem.append(currElem) # Append it to "newline"
global distance
distance = 0
x_prev = None
for x in tree.xpath('//text'):
idxList = []
bb = x.attrib.get('bbox')
if bb is not None:
bb = bb.split(',')
#print('This: ', bb)
if x_prev is not None:
#print(' Previous: ', x_prev)
distance = float(bb[0]) - float(x_prev[0])
else:
print(' No previous bbox')
# Store this bounding box for the next loop (to be used as x_prev)
x_prev = bb
if distance > 20:
for elem in x:
par = elem.getparent()
idx = par.index(elem)
idxList.append(idx)
else: # "Wrong" element, wrap elements "gathered" so far
wrap(x, idxList)
idxList = []
# Process "good" elements without any "bad" after them, if any
wrap(x, idxList)
print(etree.tostring(root, encoding='unicode', pretty_print=True))