我正在测试复杂的逻辑,这些逻辑需要将中央事实表与10-20个较小的维表连接在一起。我想模拟那10-20个较小的表。
如何在for循环中修补方法返回的值?请参见下面的代码。
tables.py:
class BaseClass(object):
def load(path: str):
...
class SmallTable1(BaseClass):
def load():
super().load(self.path)
class SmallTable20(BaseClass):
def load():
super().load(self.path)
test_logic.py
# QUESTION - how to make it work
def test_not_work(datasets):
for i in range(1, 21):
table = 'SmallTable' + str(i)
with mock.patch('some_package.tables.{}.load'.format(table)) as load_mock:
load_mock.return_value = datasets[table]
do_joins() # here my mocks doesn't work
def test_works(datasets):
with mock.patch('some_package.tables.SmallTable1.load'.format(i)) as load_mock_1:
load_mock_1.return_value = datasets[SmallTable1]
with mock.patch('some_package.tables.SmallTable2.load'.format(i)) as load_mock_2:
load_mock_2.return_value = datasets[SmallTable2]
..... # repeat the same 8-18 times more
do_joins() # here my mocks do work, but with cumbersome code and huge right offset
P.S。或者,我可以尝试模拟BaseClass.load
,但是然后我不知道如何为不同的表(类)返回不同的数据集。
答案 0 :(得分:1)
假设do_join
将在循环的 外被调用,并修补了所有表,则可以编写一个使用contextlib.ExitStack来设置所有模拟的夹具:>
from contextlib import ExitStack
from unittest import mock
import pytest
from some_package import do_join
@pytest.fixture
def datasets():
...
@pytest.fixture
def mock_tables(datasets):
with ExitStack() as stack:
for i in range(1, 21):
table = 'SmallTable' + str(i)
load_mock = stack.enter_context(
mock.patch('some_package.tables.{}.load'.format(table)))
load_mock.return_value = datasets[table]
yield
def test_join(mock_tables):
do_join()
这意味着所有模拟在屈服时仍处于活动状态,并且仅在测试完成后才会删除。
如果已安装pytest-mock
,则可以改用mocker
固定装置:
@pytest.fixture
def mock_tables(datasets, mocker):
for i in range(1, 21):
table = 'SmallTable' + str(i)
load_mock = mocker.patch('some_package.tables.{}.load'.format(table))
load_mock.return_value = datasets[table]
yield