如何从查询中获取一些信息

Question

我将shopify实施到ios应用中。到目前为止，我已经能够获得我的产品。我正在使用移动团购SDK库。 我如何设法从产品中获得单个信息，例如标题或说明。 到目前为止，我只获得了整个产品，看起来像：

[产品：[“ totalInventory”：null，“描述”：Tolles TShirt，“ id”：Z2lkOi8vc2hvcGlmeS9Qcm9kdWN0LzQNzUzMzUxMTQ4ODY =，“ productType”：，“ title”：Tee]，产品：[“ deproductType”： ：，“ id”：Z2lkOi8vc2hvcGlmeS9Qcm9dWN0LzQ0NzIwMDMyMzE4Nzg =，“ totalInventory”：，“ title”：连帽衫]]

  func findProducts(){
        let query = Storefront.buildQuery { $0
            .shop { $0
                .collections(first: 10) { $0
                    .edges { $0
                        .node { $0
                            .id()
                            .title()
                            .products(first: 10) { $0
                                .edges { $0
                                    .node { $0
                                        .id()
                                        .title()
                                        .totalInventory()
                                        .productType()
                                        .description()
                                    }
                                }
                            }
                        }
                    }
                }

            }
        }
        let client = Graph.Client(shopDomain: "online-app-store.myshopify.com", apiKey: "d63e690cf2dea787e9677c03979eb5ba")
                        client.cachePolicy = .cacheFirst(expireIn: 3600)

        let task = client.queryGraphWith(query) { response, error in
            let collections  = response?.shop.collections.edges.map { $0.node }
            collections?.forEach { collection in

                let products = collection.products.edges.map { $0.node }
                print("products found \(products)")

                let name =
                    let description ??
                        let id = ??


                self.data.append(all(id: "hi", name: "hi", description: collection.products.edges.description))
                print(self.data)
            }

        }
        task.resume()
    }