我成功使用readData读取16位音频文件并生成波形显示的峰值文件。但是，我在解释24位FLAC和WAV文件的PCM值时遇到了一些麻烦。
首先，24位的块大小是多少？
16位有符号值的范围为-32768到+32768，24位范围为-8388607到+8388607。
我为16位文件使用了4096字节的块大小（65536/16 = 4096）。它适用于检测峰值。
如果我使用24位进行相同的计算，则16777215/24 = 699050.625字节。我错了吗？我想我必须使用32位变量来存储24位值。但是在阅读文件时我应该使用什么块大小？ 699051？如何调整浮动数组的转换？
这是我用来为16位PCM数据生成峰值文件的完整C＃代码。我故意将24位代码留空，因为它不起作用。有些代码引用了我自己的FMOD包装器，但它应该很容易理解。
// Declare variables
FMOD.RESULT result = FMOD.RESULT.OK;
FileStream fileStream = null;
BinaryWriter binaryWriter = null;
GZipStream gzipStream = null;
bool generatePeakFile = false;
int CHUNKSIZE = 0;
uint length = 0;
uint read = 0;
uint bytesread = 0;
Int16[] left16BitArray = null;
Int16[] right16BitArray = null;
Int32[] left32BitArray = null;
Int32[] right32BitArray = null;
float[] floatLeft = null;
float[] floatRight = null;
byte[] buffer = null;
IntPtr data = new IntPtr(); // initialized properly later
WaveDataMinMax minMax = null;
try
{
// Set current file directory
m_peakFileDirectory = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location) + "\\Peak Files\\";
// Get file name from argument
string fileName = (string)e.Argument;
// Create sound system with NOSOUND
MPfm.Sound.System soundSystem = new MPfm.Sound.System(FMOD.OUTPUTTYPE.NOSOUND, string.Empty);
// Create sound
MPfm.Sound.Sound sound = soundSystem.CreateSound(fileName, false);
// Get sound format; specifically bits per sample (changes the calculations later)
SoundFormat soundFormat = sound.GetSoundFormat();
// Get the length of the file in PCM bytes
sound.BaseSound.getLength(ref length, FMOD.TIMEUNIT.PCMBYTES);
// Check if the folder for peak files exists
if (!Directory.Exists(PeakFileDirectory))
{
// Create directory
Directory.CreateDirectory(PeakFileDirectory);
}
// Generate the file name for the peak file by using the full path without special characters
string peakFilePath = PeakFileDirectory + fileName.Replace(@"\", "_").Replace(":", "_").Replace(".", "_") + ".mpfmPeak";
// Check if peak file exists
if(!File.Exists(peakFilePath))
{
// Set flag
generatePeakFile = true;
// Create peak file
fileStream = new FileStream(peakFilePath, FileMode.Create, FileAccess.Write);
binaryWriter = new BinaryWriter(fileStream);
gzipStream = new GZipStream(fileStream, CompressionMode.Compress);
}
// Check the bits per sample to determine what chunk size to get
if (soundFormat.BitsPerSample == 16)
{
// 4096 bytes for 16-bit PCM data
CHUNKSIZE = 4096;
}
else if (soundFormat.BitsPerSample == 24)
{
// 699050.625 bytes for 24-bit PCM data (???)
CHUNKSIZE = 699051;
}
// Create buffer
data = Marshal.AllocHGlobal(CHUNKSIZE);
buffer = new byte[CHUNKSIZE];
// Loop through file using chunk size
do
{
// Check for cancel
if (m_workerWaveForm.CancellationPending)
{
return;
}
// Check the bits per sample
if (soundFormat.BitsPerSample == 16)
{
// Read data chunk (4096 bytes for 16-bit PCM data)
result = sound.BaseSound.readData(data, (uint)CHUNKSIZE, ref read);
Marshal.Copy(data, buffer, 0, CHUNKSIZE);
bytesread += read;
// Is freehglobal needed? it crashes after one use.
//Marshal.FreeHGlobal(data);
// Convert the byte (8-bit) arrays into a short (16-bit) arrays (signed values)
left16BitArray = new Int16[buffer.Length / 4];
right16BitArray = new Int16[buffer.Length / 4];
// Loop through byte (8-bit) array buffer; increment by 4 (i.e. 4 times more data in 16-bit than 8-bit)
for (int i = 0; i < buffer.Length; i = i + 4)
{
// Convert values to 16-bit
left16BitArray[i / 4] = BitConverter.ToInt16(buffer, i);
right16BitArray[i / 4] = BitConverter.ToInt16(buffer, i + 2); // alternate between left and right channel
}
// Convert the short arrays to float arrays (signed values)
// This will convert the -32768 to 32768 value range to -1 to 1 (useful for wave display)
floatLeft = new float[left16BitArray.Length];
floatRight = new float[left16BitArray.Length];
for (int i = 0; i < left16BitArray.Length; i++)
{
// 16-bit data for unsigned values range from 0 to 65536.
floatLeft[i] = left16BitArray[i] / 65536.0f;
floatRight[i] = right16BitArray[i] / 65536.0f;
}
}
else if (soundFormat.BitsPerSample == 24)
{
// (non-working code removed)
// (I have no idea if this works) Convert the short arrays to float arrays (signed values)
// This will convert the -8388608 to 8388608value range to -1 to 1 (useful for wave display)
floatLeft = new float[left32BitArray.Length];
floatRight = new float[left32BitArray.Length];
for (int i = 0; i < left32BitArray.Length; i++)
{
// 16-bit data for unsigned values range from 0 to 16777215.
floatLeft[i] = left32BitArray[i] / 16777215.0f;
floatRight[i] = right32BitArray[i] / 16777215.0f;
}
}
// Calculate min/max
minMax = AudioTools.GetMinMaxFromWaveData(floatLeft, floatRight, false);
WaveDataHistory.Add(minMax);
// Report progress
m_bytesRead = bytesread;
m_totalBytes = length;
m_percentageDone = ((float)bytesread / (float)length) * 100;
// Write peak information to hard disk
if (generatePeakFile)
{
// Write peak information
binaryWriter.Write((double)minMax.leftMin);
binaryWriter.Write((double)minMax.leftMax);
binaryWriter.Write((double)minMax.rightMin);
binaryWriter.Write((double)minMax.rightMax);
binaryWriter.Write((double)minMax.mixMin);
binaryWriter.Write((double)minMax.mixMax);
}
}
while (result == FMOD.RESULT.OK && read == CHUNKSIZE);
// Release sound from memory
sound.Release();
// Close sound system and release from memory
soundSystem.Close();
soundSystem.Release();
// Set nulls for garbage collection
sound = null;
soundSystem = null;
left16BitArray = null;
right16BitArray = null;
left32BitArray = null;
right32BitArray = null;
floatLeft = null;
floatRight = null;
buffer = null;
minMax = null;
}
catch (Exception ex)
{
throw ex;
}
finally
{
// Did we have to generate a peak file?
if (generatePeakFile)
{
// Close writer and stream
gzipStream.Close();
binaryWriter.Close();
fileStream.Close();
// Set nulls
gzipStream = null;
binaryWriter = null;
fileStream = null;
}
}
// Call garbage collector
GC.Collect();
以下是从float数组中提取最小/最大值的方法：
/// <summary>
/// This method takes the left channel and right channel wave raw data and analyses it to get
/// the maximum and minimum values in the float structure. It returns a data structure named
/// WaveDataMinMax (see class description for more information). Negative values can be converted to
/// positive values before min and max comparaison. Set this parameter to true for output meters and
/// false for wave form display controls.
/// </summary>
/// <param name="waveDataLeft">Raw wave data (left channel)</param>
/// <param name="waveDataRight">Raw wave data (right channel)</param>
/// <param name="convertNegativeToPositive">Convert negative values to positive values (ex: true when used for output meters,
/// false when used with wave form display controls (since the negative value is used to draw the bottom end of the waveform).<</param>
/// <returns>WaveDataMinMax data structure</returns>
public static WaveDataMinMax GetMinMaxFromWaveData(float[] waveDataLeft, float[] waveDataRight, bool convertNegativeToPositive)
{
// Create default data
WaveDataMinMax data = new WaveDataMinMax();
// Loop through values to get min/max
for (int i = 0; i < waveDataLeft.Length; i++)
{
// Set values to compare
float left = waveDataLeft[i];
float right = waveDataRight[i];
// Do we have to convert values before comparaison?
if (convertNegativeToPositive)
{
// Compare values, if negative then remove negative sign
if (left < 0)
{
left = -left;
}
if (right < 0)
{
right = -right;
}
}
// Calculate min/max for left channel
if (left < data.leftMin)
{
data.leftMin = left;
}
if (left > data.leftMax)
{
data.leftMax = left;
}
// Calculate min/max for right channel
if (right < data.rightMin)
{
data.rightMin = right;
}
if (right > data.rightMax)
{
data.rightMax = right;
}
// Calculate min/max mixing both channels
if (left < data.mixMin)
{
data.mixMin = left;
}
if (right < data.mixMin)
{
data.mixMin = right;
}
if (left > data.mixMax)
{
data.mixMax = left;
}
if (right > data.mixMax)
{
data.mixMax = right;
}
}
return data;
}
任何人都可以给我一个暗示该做什么的提示吗？我希望我的代码不是太糟糕，可以用作16位文件的示例。谢谢你的帮助！
修改
这是使用32位可变转换代码的3x8位到24位：
left32BitArray = new Int32[buffer.Length / 6];
right32BitArray = new Int32[buffer.Length / 6];
for (int i = 0; i < buffer.Length; i = i + 6)
{
// Create smaller array in order to add the 4th 8-bit value
byte[] byteArrayLeft = new byte[4] {buffer[i], buffer[i + 1], buffer[i + 2], 0 };
byte[] byteArrayRight = new byte[4] { buffer[i + 3], buffer[i + 4], buffer[i + 5], 0 };
// Convert values to 32-bit variables
left32BitArray[i / 6] = BitConverter.ToInt32(byteArrayLeft, 0);
right32BitArray[i / 6] = BitConverter.ToInt32(byteArrayRight, 0);
}
答案 0 :(得分：0)
24位音频文件具有3 *通道数的块对齐。为什么不去寻找100ms的音频：
int blockSize = 3 * channels * (sampleRate / 10);
这适用于24位WAV。您的FLAC阅读器是否允许您读取该粒度取决于其内部实现。