如何解决编译器警告

时间:2020-05-23 11:19:33

标签: java android android-room

我收到此编译器警告: 对上面的代码使用未经检查或不安全的操作

resource "aws_iam_policy" "policy" {
  name = "my-role"
   description = "My policy"

  policy = <<-EOF
{
    "Version": "2012-10-17",
    "Statement": [
      {
        "Sid": "Stmt1590217939128",
        "Action": "s3:*",
        "Effect": "Allow",
        "Resource": "arn:aws:s3:::wwe"
      },
      {
        "Sid": "Stmt1590217939125",
        "Action": "s3:*",
        "Effect": "Allow",
        "Resource": "arn:aws:s3:::wwe/*"
      },
      {
        "Sid": "Stmt1577967806846",
        "Action": [
          "secretsmanager:DescribeSecret",
          "secretsmanager:GetRandomPassword",
          "secretsmanager:GetResourcePolicy",
          "secretsmanager:GetSecretValue",
          "secretsmanager:ListSecretVersionIds",
          "secretsmanager:ListSecrets"
        ],
        "Effect": "Allow",
        "Resource": "*"
      }
    ]
}
EOF
}

resource "aws_iam_role_policy_attachment" "test-attach" {
  role       = "${aws_iam_role.role.name}"
  policy_arn = "${aws_iam_policy.policy.arn}"
}

但我不知道为什么,我尝试使用-Xlint params运行更多信息。

代码有效,但警告仍然存在。

希望可以为您提供帮助

整个任务:

new InsertAllTask(essenceDao).execute(essenceList)

InsertTask:

public static class DeleteAllTask extends AsyncTask<Void, Void, Void> {
    private final EssenceDao essenceDao;
    private final List<Essence> essenceList;

    DeleteAllTask(EssenceDao essenceDao, List<Essence> list) {
        this.essenceDao = essenceDao;
        this.essenceList = list;
    }

    @Override
    protected Void doInBackground(Void... voids) {
        essenceDao.deleteAllEssence();
        return null;
    }

    @Override
    protected void onPostExecute(Void aVoid) {
        super.onPostExecute(aVoid);
        if (essenceList != null) {
            // Insert new list
            new InsertAllTask(essenceDao).execute(essenceList);
        }
    }
}

1 个答案:

答案 0 :(得分:0)

由于您要在不修复警告源的情况下禁止显示警告(-Xlint),因此可以将此注释添加到包含不安全代码的方法中:

    @SuppressWarnings({"unused", "rawtypes"})

示例

上面的代码:

    public class TestUnsafe {
      public static void main(String[] args) {
        List myList = new ArrayList();
      }
    }

在尝试编译时显示以下警告:

javac TestUnsafe.java -Xlint

    TestUnsafe.java:7: warning: [rawtypes] found raw type: List
        List myList = new ArrayList();
        ^
      missing type arguments for generic class List<E>
      where E is a type-variable:
        E extends Object declared in interface List
    TestUnsafe.java:7: warning: [rawtypes] found raw type: ArrayList
        List myList = new ArrayList();
                          ^
      missing type arguments for generic class ArrayList<E>
      where E is a type-variable:
        E extends Object declared in class ArrayList
    2 warnings

但是,使用几个注释:

    public class TestUnsafe {
      @SuppressWarnings({"unused", "rawtypes"})
      public static void main(String[] args) {
        List myList = new ArrayList();
      }
    }

javac TestUnsafe.java -Xlint返回一个空的编译日志。

为我们提供一个最小的可复制示例,以查找正确的注释或对其进行修复!

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