Question

可能重复：
How do I disambiguate in Scala between methods with vararg and without

我目前正在将应用程序的一部分移植到scala，它使用Oval库。方法问题是Validator.validate方法。它有two signatures：

List<ConstraintViolation> validate(Object validatedObject)
List<ConstraintViolation> validate(Object validatedObject, String... profiles)

scala代码看起来像这样：

def validate(toValidate: AnyRef) = {
  val validator = createValidator
  validator.validate(toValidate)
}

错误信息：

error: ambiguous reference to overloaded definition,
[INFO] both method validate in class Validator of type (x$1: Any,x$2: <repeated...>[java.lang.String])java.util.List[net.sf.oval.ConstraintViolation]
[INFO] and  method validate in class Validator of type (x$1: Any)java.util.List[net.sf.oval.ConstraintViolation]
[INFO] match argument types (AnyRef)
[INFO]       this.validator.validate(toValidate)

我怎样才能明白这一点？

Answer 1

我认为这可能与How do I disambiguate in Scala between methods with vararg and without

重复

基本上，它是一个已知的java-scala-interop问题，唯一的解决方法是在Scala中使用额外的Java适配器。

Answer 2

我所知道的唯一方法是使用反射：

val ambiguous = validator.getClass.getMethods.filter(_.getName == "validate")
val wanted = ambiguous.find(_.getParameterTypes.length == 1).get
wanted.invoke(validator, toValidate).asInstanceOf[java.util.List[ConstraintViolation]]

Scala - 对重载定义的模糊引用 - 使用varargs

2 个答案: