Question

我正在尝试从Java Web App的输入中简单地将base64加密密码存储在数据库中。

我为此使用hsqldb，我的密码列类型为varbinary（255）。但是，当我尝试将其存储在数据库中时，只会出现以下错误。我什至尝试将密码列的类型更改为BLOB或varchar，但仍然会出现相同的错误。请帮忙。

错误：

com.loginjava.exception.LoginException: Not possible to update the password
    at com.loginjava.classes.PasswordHandler.UpdatePassword(PasswordHandler.java:36)
    at com.loginjava.servlets.ForgotPasswordReset.doPost(ForgotPasswordReset.java:55)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:660)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:741)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:231)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:53)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:193)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:166)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:202)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:96)
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:541)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:139)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:92)
    at org.apache.catalina.valves.AbstractAccessLogValve.invoke(AbstractAccessLogValve.java:690)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:74)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:343)
    at org.apache.coyote.http11.Http11Processor.service(Http11Processor.java:373)
    at org.apache.coyote.AbstractProcessorLight.process(AbstractProcessorLight.java:65)
    at org.apache.coyote.AbstractProtocol$ConnectionHandler.process(AbstractProtocol.java:868)
    at org.apache.tomcat.util.net.NioEndpoint$SocketProcessor.doRun(NioEndpoint.java:1590)
    at org.apache.tomcat.util.net.SocketProcessorBase.run(SocketProcessorBase.java:49)
    at java.base/java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1128)
    at java.base/java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:628)
    at org.apache.tomcat.util.threads.TaskThread$WrappingRunnable.run(TaskThread.java:61)
    at java.base/java.lang.Thread.run(Thread.java:830)
Caused by: java.sql.SQLDataException: data exception: invalid character value for cast
    at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
    at org.hsqldb.jdbc.JDBCUtil.sqlException(Unknown Source)
    at org.hsqldb.jdbc.JDBCPreparedStatement.setParameter(Unknown Source)
    at org.hsqldb.jdbc.JDBCPreparedStatement.setString(Unknown Source)
    at org.apache.tomcat.dbcp.dbcp2.DelegatingPreparedStatement.setString(DelegatingPreparedStatement.java:616)
    at org.apache.tomcat.dbcp.dbcp2.DelegatingPreparedStatement.setString(DelegatingPreparedStatement.java:616)
    at com.loginjava.classes.PasswordHandler.UpdatePassword(PasswordHandler.java:26)
    ... 25 more
Caused by: org.hsqldb.HsqlException: data exception: invalid character value for cast
    at org.hsqldb.error.Error.error(Unknown Source)
    at org.hsqldb.error.Error.error(Unknown Source)
    at org.hsqldb.Scanner.convertToBinary(Unknown Source)
    at org.hsqldb.types.BinaryType.castOrConvertToType(Unknown Source)
    at org.hsqldb.types.BinaryType.convertToDefaultType(Unknown Source)
    ... 30 more

这是我的Servlet：

    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {

        String password = request.getParameter("password");
        String token = request.getParameter("token");
                if(PasswordHandler.CheckRequirements(password)) {

                    String encryptedpwd = Base64.getEncoder().encodeToString(password.getBytes());
                    try {
                        PasswordHandler.UpdatePassword(encryptedpwd, token);
                    } catch (SQLException e) {

                        e.printStackTrace();
                    }


                String message = Constants.PWD_SUCCESS;
                request.setAttribute("message", message);
                request.getRequestDispatcher("reset-password.jsp?token=" + token).forward(request, response);   

            } else {

                String message = Constants.PWD_FAIL;
                request.setAttribute("message", message);
                request.getRequestDispatcher("reset-password.jsp?token=" + token).forward(request, response);   
            }



    }

这是PasswordHandler.java类：

public static void UpdatePassword(String encryptedpwd, String token) throws SQLException {

            try
              {
               PreparedStatement ps = con.prepareStatement(
                  "UPDATE user SET password = ? WHERE token = ?");

                ps.setString(1,encryptedpwd);
                ps.setString(2,token);

                ps.executeUpdate();

                ps.close();


              }
            catch (Exception e) {
                 throw new LoginException("Not possible to update the password", e);
              }


            }

Answer 1

您已将密码列定义为varbinary（255）。插入到这种类型的列中的任何字符串都必须采用十六进制格式，例如cd349956e2。您可以使用编码器将密码转换为二进制数组，然后在插入之前将二进制转换为十六进制。

或者您可以将列定义为varchar（255），以将密码作为base64字符串插入。

在任何情况下，密码通常都不直接存储在数据库中，而是作为安全哈希存储。例如SHA-256哈希。

Answer 2

在这里添加一个可能的解决方案，因为我的水平不允许我发表评论。

在此行：

PasswordHandler.UpdatePassword(encryptedpwd, token);

验证变量 encryptedpwd 的值和长度，检查数据库是否接受类型值（可能为null）和变量的长度（可能长于DB中允许的长度）。

加密（base64）密码未存储在数据库hsql中

2 个答案: