假设我有三个班级
@Entity
public class Book {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@Column
private String name;
}
@Entity
public class Author {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@Column
private String fistName;
@Column
private String lastName;
}
@Entity
public class AuthorBookRelation {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@ManyToOne
@JoinColumn(name = "author", referencedColumnName = "id")
private Author author;
@ManyToOne
@JoinColumn(name = "book", referencedColumnName = "id")
private Book book;
}
因此,我有三个Qclass
QAuthor QBook QAuthorBookRelation。
但是我只能做两节课。
@Entity
public class Book {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@Column
private String name;
}
@Entity
public class Author {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
@Column
private String fistName;
@Column
private String lastName;
@ManyToMany
@JoinTable(
name = "author_book_relation",
joinColumns = {@JoinColumn(name = "author")},
inverseJoinColumns = {@JoinColumn(name = "book")}
)
private List<Book> books = new ArrayList<>();
}
然后,不需要类AuthorBookRelation。 但是我需要QAuthorBookRelation来创建带有queryDSL的请求
如何创建绑定到两个表的类?
答案 0 :(得分:0)
我认为您缺少JPA,JPQL和QueryDSL的要点。您应该加入关联的实体。除非您需要将数据与该关联相关联,否则在任何这些技术中绝对不需要关联实体。
否则,您只需要这样做:
List<Tuple> result = query().from(QBook.book)
.innerJoin(QBook.book.author, author)
.select(QBook.book, QAuthor.author)
.fetch();
等同于以下JPQL:
SELECT book, author FROM Book book INNER JOIN book.author author