Question

当在where子句中添加AND icutype = $ icutype时，我没有错误，也没有$ con2和$ con3的值。删除后，我正确地获得了总输出。

<?Php
$con = mysqli_connect("localhost","root","","nimicudb");
$con2 = mysqli_connect("localhost","root","","nimicudb");
$con3 = mysqli_connect("localhost","root","","nimicudb");
if (mysqli_connect_errno()){
    echo "Failed to connect to MySQL: " . mysqli_connect_error();
    die();
}

if(!empty($_POST) && $_SERVER['REQUEST_METHOD'] == 'POST'){

    $icutype = $_POST["icutype"];
    $fromdate = $_POST['fromdate'];
    $todate = $_POST['todate'];

    $sql1= mysqli_query($con,"SELECT COUNT(name) FROM `patients` WHERE date BETWEEN '$fromdate' AND '$todate' AND icutype = '$icutype'");
    $row = mysqli_fetch_array($sql1);
    $totalpatients=$row[0];

    $sql2= mysqli_query($con,"SELECT icubedstrength FROM `icustrength` WHERE icuname = '$icutype' ");
    $row1 = mysqli_fetch_array($sql2);
    $totalbeds=$row1[0];

    $sql3= mysqli_query($con2,"SELECT COUNT(icureturn48) FROM `patients1` WHERE date BETWEEN '$fromdate' AND '$todate' AND icutype = '$icutype' ");
    $row2 = mysqli_fetch_array($sql3);
    $totalicureturn48=$row2[0];

    $sql4= mysqli_query($con,"SELECT COUNT(datedischarge) FROM `patients` WHERE date BETWEEN '$fromdate' AND '$todate' AND icutype = '$icutype'");
    $row3 = mysqli_fetch_array($sql4);
    $totaldischarge=$row3[0];

    $sql5= mysqli_query($con3,"SELECT COUNT(reintbn48) FROM `patients2` WHERE date BETWEEN '$fromdate' AND '$todate' AND icutype = '$icutype'");
    $row4 = mysqli_fetch_array($sql5);
    $totalreintubation=$row4[0];

    $sql6= mysqli_query($con,"SELECT COUNT(tubedate) FROM `patients` WHERE date BETWEEN '$fromdate' AND '$todate' AND icutype = '$icutype'");
    $row5 = mysqli_fetch_array($sql6);
    $totalintubation=$row5[0];

    $totaldays = (strtotime($todate) - strtotime($fromdate)) / (60 * 60 * 24);
    echo  "TOTAL DAYS - $totaldays </br>";
    echo "TOTAL PATIENTS - $totalpatients</br>";
    echo "TOTAL BEDS - $totalbeds</br>";
    echo "TOTAL discharge - $totaldischarge</br>";
    echo "TOTAL intubation - $totalintubation</br>";
    echo "TOTAL PATIENTS returned - $totalicureturn48</br>";
    echo "TOTAL reintubation - $totalreintubation</br>";

    $icureturnrate=(round(($totalicureturn48/$totaldischarge)*100));
    $reintubation_rate=(round(($totalreintubation/$totalintubation)*100));
    $urate=(round(($totalpatients/$totalbeds)*$totaldays));
    echo "utilization rate is  : $urate</br>";
    echo "% Return to ICU within 48 hours is  : $icureturnrate </br>";
    echo "% Re-intubation rate is  : $reintubation_rate";
}
?>



<html>


<form action='search.php' method='POST'>
<h5>SELECT ICU</h5>
<select name='icutype' >

    <option value="EICU">EICU</option>
    <option value="NMICU">NMICU</option>
    <option value="NSICU">NSICU</option>
    <option value="SBICU">SBICU</option>
</select>

</br>


    FROM DATE<input type="date" name="fromdate" value="<?php echo date('Y-m-d', strtotime('-30 days')); ?>"></br>


  TO DATE<input type="date" name="todate" value="<?php echo date('Y-m-d'); ?>"></br>


<input type='submit' name='calsubmit' value="CALCULATE"/>
</form>



</html>

这是我需要咨询的页面。

此显示的输出如下

TOTAL DAYS - 30
TOTAL PATIENTS - 1
TOTAL BEDS - 6
TOTAL discharge - 1
TOTAL intubation - 1
**TOTAL PATIENTS returned - 0
**TOTAL reintubation - 0
utilization rate is : 5
% Return to ICU within 48 hours is : 0
% Re-intubation rate is : 0

**标记的项目在添加和添加到条款（AND icutype = '$icutype'）时没有提供任何输出

Answer 1

伙计们，我整理了一下。问题是一些空白与icutype列中的数据一起保存了。我将icutype = $ icutype更改为icutype LIKE'％$ icutype％'，它像地狱般工作。谢谢大家。

从多个表中获取数据-单个数据库

1 个答案: