我的数据结构就像数组中的数组。我有一个名为id(int),元(JSONB)的2列表,数据存储如下:
id : meta
12 : [... ]
[...]如下所示:
[
{
"task": "T3",
"task_label": "what is wrong.",
"value": "Something's wrong"
},
{
"task": "T0",
"task_label": "What's wrong about this image?",
"value": [
{
"x": 228.52696228027344,
"y": 42.95765686035156,
"tool": 0,
"frame": 0,
"width": 738.8717193603516,
"height": 45.10553741455078,
"details": [],
"tool_label": "Sender"
},
{
"x": 1302.4683837890625,
"y": 642.2169799804688,
"tool": 2,
"frame": 0,
"width": 423.1329345703125,
"height": 115.98565673828125,
"details": [],
"tool_label": "Action"
}
]
}
]
我想运行sql查询以找到所有task_label的列表,其中task =“ T0”。
结果应该像
id: meta->task->value->tool_label
12: Sender, Action
答案 0 :(得分:1)
您可以使用jsonb_array_elements()
两次,然后进行过滤和汇总:
select t.id, string_agg(l2.obj ->> 'tool_label', ',') tool_labels
from mytable t
cross join lateral jsonb_array_elements(t.meta) as l1(obj)
cross join lateral jsonb_array_elements(l1.obj -> 'value') as l2(obj)
where l1.obj ->> 'task' = 'T0'
group by t.id