Question

我在ClickHouse中使用此查询：

SELECT DISTINCT
  iap.EventId,
  iap.Id as Title,
  ole.RewardId,
  ole.RewardGain,
  if((ole.RewardType = 'Currency' and ole.RewardId = 'Cash'), ole.RewardGain, null) as Soft
FROM OpenLootboxEvent ole 
ANY LEFT OUTER JOIN InAppPurchaseEvent iap
ON ole.EventSourceId = iap.EventId
WHERE iap.Id in ('superHotDeal');

此查询返回结果：

EventId  Title         RewardId  Gain  
---------------------------------------------------------------------
111      superHotDeal  m3        5    
111      superHotDeal  m14       13         
111      superHotDeal  m20       25         
111      superHotDeal  Cash      282            
111      superHotDeal  Talent    null   
111      superHotDeal  Hard      null

每个“ EventId”和“ Title”具有6个含义，其中“ RewardId”的值可以从“ m1”到“ m26”，并且始终可以具有“现金”，“人才”，“硬”值。

如何在同一行中检索具有相同“ EventId”和“ Title”的所有行？

赞：

EventId  Title         man1  man1Cards   man2  man2Cards   man3  man3Cards  Cash  Talent  Hard                     
----------------------------------------------------------------------------------------------
111      superHotDeal  m3  5             m14   13          m20   25         282   null    null

Answer 1

select EventId, Title, groupArray(tuple(RewardId, RewardGain))
from (
SELECT DISTINCT
  iap.EventId EventId,
  iap.Id as Title,
  ole.RewardId RewardId,
  ole.RewardGain RewardGain,
  if((ole.RewardType = 'Currency' and ole.RewardId = 'Cash'), ole.RewardGain, null) as Soft
FROM OpenLootboxEvent ole 
ANY LEFT OUTER JOIN InAppPurchaseEvent iap
ON ole.EventSourceId = iap.EventId
WHERE iap.Id in ('superHotDeal'))
group by EventId, Title

Pivot In clickhouse

如何在ClickHouse中将具有相同列值的mysql行分组为一行？

1 个答案: