php正则表达式分割字符串[%%%]

Question

嗨我需要一个preg_split正则表达式，它会在方括号中的子串处拆分一个字符串。

此示例输入：

$string = 'I have a string containing [substrings] in [brackets].';

应提供此数组输出：

[0]= 'I have a string containing '
[1]= '[substrings]'
[2]= ' in '
[3]= '[brackets]'
[4]= '.'

Answer 1

阅读修改后的问题：

这可能是你想要的：

$string = 'I have a string containing [substrings] in [brackets].';
preg_split('/(\[.*?\])/', $string, null, PREG_SPLIT_DELIM_CAPTURE);

你应该得到：

Array
(
    [0] => I have a string containing 
    [1] => [substrings]
    [2] =>  in 
    [3] => [brackets]
    [4] => .
)

原始回答：

preg_split('/%+/i', 'ot limited to 3 %%% so it can be %%%% or % or %%%%%, etc Tha');

你应该得到：

Array
(
    [0] => ot limited to 3 
    [1] =>  so it can be 
    [2] =>  or 
    [3] =>  or 
    [4] => , etc Tha
)

或者如果您想要最小值3，请尝试：

preg_split('/%%%+/i', 'Not limited to 3 %%% so it can be %%%% or % or %%%%%, etc Tha');

快去http://regex.larsolavtorvik.com/

Answer 2

我认为这就是你要找的东西：

$array = preg_split('/(\[.*?\])/', $string, null, PREG_SPLIT_DELIM_CAPTURE);