Question

我有一个按钮在我的活动中显示搜索栏，十秒钟后，我隐藏了搜索栏，但是如果用户在10秒之前按下按钮以隐藏搜索栏，则后延迟必须重新启动或停在使用的代码下方。我如何停止后延迟？

 barraBrilho.setVisibility(View.GONE);

    brilho.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            if (!gone) {

                Animation anim = AnimationUtils.loadAnimation(getActivity(),R.anim.translate_layout_right );
                barraBrilho.startAnimation(anim);
                barraBrilho.setVisibility(View.GONE);

                gone = true;
            }

    else{ barraBrilho.setVisibility(View.VISIBLE);
        Animation anim = AnimationUtils.loadAnimation(getActivity(),R.anim.translate_layout_left);
        barraBrilho.startAnimation(anim);
        gone = false;

                new Handler().postDelayed( new Runnable() {
                    @Override
                    public void run() {
                        Animation anim = AnimationUtils.loadAnimation( getActivity(), R.anim.translate_layout_right );
                        barraBrilho.startAnimation( anim );
                        barraBrilho.setVisibility( View.GONE );
                        gone = true;
                    }
                }, 10000 );

            }
        }
    } );

Answer 1

当用户单击brilho按钮时，调用handler.removeCallbacks（可运行）。

class ansBtnListener implements ActionListener {
    int count = 0;
    public void actionPerformed(ActionEvent e) {
    // checking answer is correct or wrong
        double doubleOfInput = Double.parseDouble(input.getText()); // getting string to double
        if (doubleOfInput == result && count==0) {
            JOptionPane.showMessageDialog(null, "Correct");
            count++;
        }
        else if (doubleOfInput == result && count==1) {
            JOptionPane.showMessageDialog(null, "Great Job!");
            count++;
        }
        else if (doubleOfInput == result && count==2) {
            JOptionPane.showMessageDialog(null, "Excellent!");
            count++;
        }
        else if (doubleOfInput == result && count>2) {
            JOptionPane.showMessageDialog(null, "Please click on end!");
        }
        else {
            JOptionPane.showMessageDialog(null, "Wrong, Try Again!");
            input.setText(" ");
        }
    }
}

我建议您创建Runnable的子类，并通过WeakReference引用Activity实例

Handler handler = new Handler();
Runnable runnable = new Runnable();

handler.removeCallbacks(runnable);

停止或重新启动Handler.postdelayed

1 个答案: