Question

我正在使用Oracle数据库，并且使用联接编写了一个SQL查询，如下所示：

SELECT
(CT.CRDATTIM || CT.RECORDCD || CT.CRNODE) AS CALLERKEY 
FROM
   W67U999S F 
   JOIN
      W03U999S CT 
      ON F.CCRDATTIM = CT.CRDATTIM 
      AND F.CRECORDCD = CT.RECORDCD 
      AND F.CCRNODE = CT.CRNODE 
      AND F.CRECORDCD = 'T' 
      AND CT.WRKTYPE = 'CALLER' 
   JOIN
      PQCUSTSRV CDT 
      ON F.CCRDATTIM = CDT.CRDATTIM 
      AND F.CRECORDCD = CDT.RECORDCD 
      AND F.CCRNODE = CDT.CRNODE 
WHERE
   F.PCRDATTIM = '2019-01-29-06.10.33.037940' 
   AND F.PRECORDCD = 'F' 
   AND F.PCRNODE = '01' 
   AND CT.CRDATTIM < '9999-12-31-23.59.59.999999'

以上查询返回了以下几行数据：

CALLERKEY
----------
2019-01-29-06.10.33.310940T01
2019-03-26-00.51.05.124040T01
2019-03-26-00.51.07.993040T01
2019-03-26-00.51.35.531040T01
2019-04-02-04.02.42.280040T01

现在，我想使用以下SQL查询来查询每一行，以获取我感兴趣的一些其他数据：示例如下：

SELECT COUNT(*) AS TESTCOUNT FROM PQCUSTSRV where CALLERKEY='2019-01-29-06.10.33.310940T01' AND TO_TIMESTAMP(CRDATTIM,'YYYY-MM-DD HH24.MI.SS.FF') 
      BETWEEN ADD_MONTHS(SYSTIMESTAMP,-12) AND SYSTIMESTAMP

上面的查询返回以下数据：

TESTCOUNT
------------
2

现在，我想结合以上两个查询，并获得如下所示的输出：

CALLERKEY                           TESTCOUNT                                               
----------                          --------    
2019-01-29-06.10.33.310940T01       2
2019-03-26-00.51.05.124040T01       3       
2019-03-26-00.51.07.993040T01       2
2019-03-26-00.51.35.531040T01       1
2019-04-02-04.02.42.280040T01       4

我该如何实现？请让我知道是否需要其他信息。

Answer 1

with t as (
      <first query here>
     )
select t.callerkey, count(p.callerkey) AS TESTCOUNT
from t left join
     PQCUSTSRV p
     on p.callerkey = t.callerkey and
        to_timestamp(p.CRDATTIM, 'YYYY-MM-DD HH24.MI.SS.FF') >= add_months(SYSTIMESTAMP, -12) 
group by t.callerkey;

我将日期比较的逻辑更改为仅使用>=，假设您在crdattim中没有将来的值。

Answer 2

您可以按以下方式使用group by：

Select F.CALLERKEY, COUNT(1) AS CNT
  From (your_first_query) f
  Left Join PQCUSTSRV s
    On s.CALLERKEY=f.CALLERKEY AND TO_TIMESTAMP(CRDATTIM,'YYYY-MM-DD HH24.MI.SS.FF') 
      BETWEEN ADD_MONTHS(SYSTIMESTAMP,-12) AND SYSTIMESTAMP  
 Group by f.callerkey

Answer 3

未经测试，但这应该可以工作

SELECT A.CALLERKEY, COUNT(*) AS TESTCOUNT 
(SELECT (CT.CRDATTIM || CT.RECORDCD || CT.CRNODE) AS CALLERKEY
   FROM W67U999S F
        JOIN W03U999S CT
           ON     F.CCRDATTIM = CT.CRDATTIM
              AND F.CRECORDCD = CT.RECORDCD
              AND F.CCRNODE = CT.CRNODE
              AND F.CRECORDCD = 'T'
              AND CT.WRKTYPE = 'CALLER'
        JOIN PQCUSTSRV CDT
           ON     F.CCRDATTIM = CDT.CRDATTIM
              AND F.CRECORDCD = CDT.RECORDCD
              AND F.CCRNODE = CDT.CRNODE
  WHERE     F.PCRDATTIM = '2019-01-29-06.10.33.037940'
        AND F.PRECORDCD = 'F'
        AND F.PCRNODE = '01'
        AND CT.CRDATTIM < '9999-12-31-23.59.59.999999')A, PQCUSTSRV B
 WHERE A.CALLERKEY=B.CALLERKEY AND TO_TIMESTAMP(CRDATTIM,'YYYY-MM-DD HH24.MI.SS.FF')
      BETWEEN ADD_MONTHS(SYSTIMESTAMP,-12) AND SYSTIMESTAMP
 GROUP BY B.CALLERKEY

结合两个SQL查询及其结果

3 个答案: