Question

如何在PyQt5中获取当前关注的小部件objectName？这是我的代码。在我的代码中，我获得了所有小部件的对象名称。而且我也想知道重点突出的小部件objectName。

import sys

from PyQt5.QtWidgets import *
class Check(QWidget):
    
    def __init__(self):
        super().__init__()
        self.setWindowTitle("Check Window")
        self.textbox1 = QLineEdit(self)
        self.textbox1.setGeometry(100, 100, 300, 30)
        self.textbox2 = QLineEdit(self)
        self.textbox2.setGeometry(100, 150, 300, 30)
        self.textbox3 = QLineEdit(self)
        self.textbox3.setGeometry(100, 200, 300, 30)

        self.lbox1 = QListWidget()
        self.lbox2 = QListWidget(self)
        self.lbox2.setGeometry(100,250,300,500)
        self.textbox1.setObjectName("textbox1")
        self.textbox2.setObjectName("textbox2")
        self.textbox3.setObjectName("textbox3")

        self.updateallwidgets()
        self.focuwidget()

    def updateallwidgets(self):
        QWidget.allwidgets = QApplication.allWidgets()
        for i in QWidget.allwidgets:
            j = i.objectName()


    def focuwidget(self):
        fwidget = QApplication.focusWidget()
        print("focus widget name ",fwidget)

def main():
    myapp = QApplication(sys.argv)
    mywin = Check()
    mywin.show()
    sys.exit(myapp.exec_())

if __name__ == "__main__":
    main()

Answer 1

您试图在创建始终为None的窗口之前获取具有焦点的小部件，解决方案是通过focusChanged信号检测焦点何时发生变化：

class Check(QWidget):
    def __init__(self):
        super().__init__()
        self.setWindowTitle("Check Window")
        self.textbox1 = QLineEdit(self)
        self.textbox1.setGeometry(100, 100, 300, 30)
        self.textbox2 = QLineEdit(self)
        self.textbox2.setGeometry(100, 150, 300, 30)
        self.textbox3 = QLineEdit(self)
        self.textbox3.setGeometry(100, 200, 300, 30)

        self.lbox1 = QListWidget()
        self.lbox2 = QListWidget(self)
        self.lbox2.setGeometry(100, 250, 300, 500)
        self.textbox1.setObjectName("textbox1")
        self.textbox2.setObjectName("textbox2")
        self.textbox3.setObjectName("textbox3")

        QApplication.instance().focusChanged.connect(self.on_focusChanged)

    def on_focusChanged(self):
        fwidget = QApplication.focusWidget()
        if fwidget is not None:
            print("focus widget name ", fwidget.objectName())

如何在PyQt5中获取当前关注的小部件对象名称？

1 个答案: