Question

我想创建一个from来更改表中记录的图像。当我将图像加载到窗体中时，图像似乎在那里，但是文件选择器控件文本显示“未选择文件”。我在做什么错了？

<html>
<body> 
    <main>
        <form name="EditForm" action="test-save-edit.php" method="POST" enctype="multipart/form-data">
<?php
$post_id = trim($_GET["id"]);
require_once "config.php";
try{
    $sql1 = "select picture from images where post_id=:post_id";    
    if($stmt1 = $pdo->prepare($sql1)){
        $stmt1->bindParam(":post_id", $post_id, PDO::PARAM_INT );
        if($stmt1->execute()){
            if($stmt1->rowCount() > 0){
                $i = 0;
                while($row1 = $stmt1->fetch()){
?>
            <input type="file" name="image<?php echo ++$i ?>" value="<?php echo base64_encode($row1['picture']) ?>"/>
<?php
                }
            }
        }
        unset($stmt1);
    }
} catch (Exception $e) {
    var_dump($e->getMessage());
    var_dump($e->getCode());
}
?>
            <input type="submit" value="Next" />
        </form>
    </main>
</body>
</html>

编辑表单未显示填充的图像

0 个答案: