Question

我正在尝试通过将while循环替换为while循环来转换代码。
这是我要转换的代码

以下代码段中的代码功能。 @Sameer询问

    from random import sample
    def shuffle(s): return sample(s,len(s)) 
    rBase = range(base)
    base  = 2
    side  = base*base
    def pattern(r,c):
        return (base*(r%base)+r//base+c)%side

我遇到问题的代码

    rows = []
    cols = []
    data = []
    for r in shuffle(rBase):
        for g in shuffle(rBase):
            rows.append(g*base+r)
    for c in shuffle(rBase):
        for g in shuffle(rBase):
            cols.append(g*base+c)
    nums = shuffle(range(1,side+1))
    for r in rows:
        for c in cols:
            data.append(nums[pattern(r,c)])

这是我尝试输入的代码

rows = []
cols = []
data = []
s = shuffle(rBase)
i,j = 0,0
while i < len(s):
    r = s[i]
    while j < len(s):
        s2 = shuffle(rBase)
        g = s2[i]
        rows.append(g*base+r)
        j+=1
    i += 1
i,j = 0,0
s = shuffle(rBase)
while i < len(s):
    c = s[i]
    while j < len(s):
        s2 = shuffle(rBase)
        g = s2[i]
        cols.append(g*base+c)
        j += 1
    i += 1
nums = shuffle(range(1,side+1))
i,j =0,0
while i < len(rows):
    r = rows[i]
    while j < len(cols):
        c = cols[i]
        data.append(nums[pattern(r,c)])
        j += 1
    i += 1

由于隐私原因，省略了部分代码。
预期的输出，即for循环代码段的输出是一个列表，该列表的长度（基数** 4）包含从1到基数** 2的每个数字，正好是基数** 2倍。例如：如果基数是2：预期的输出将像[3, 2, 1, 4, 4, 1, 3, 2, 1, 4, 2, 3, 2, 3, 4, 1]

实际输出是一个长度为base的列表，每个元素都是1到base ** 2之间的一个随机数（包括base ** 2）。例如：如果基数是2：实际输出类似于[1,1]或[2,2]或[3,3]或[4,4]

Answer 1

应在内部while循环之前定义变量j = 0。目前，您的内部仅运行“ len”次，并且在第二个循环中使用“ i”编制索引，因此您应该在其中使用j。

这应该有效

from random import sample

def shuffle(s): return sample(s,len(s)) 
base  = 2
rBase = range(base)
side  = base*base
def pattern(r,c):
    return (base*(r%base)+r//base+c)%side

rows = []
cols = []
data = []
for r in shuffle(rBase):
    for g in shuffle(rBase):
        rows.append(g*base+r)
for c in shuffle(rBase):
    for g in shuffle(rBase):
        cols.append(g*base+c)
print(rows)
print(cols)        
nums = shuffle(range(1,side+1))
for r in rows:
    for c in cols:
        data.append(nums[pattern(r,c)])

print(data)

rows = []
cols = []
data = []
s = shuffle(rBase)
s2 = shuffle(rBase)
i = 0
while i < len(s):
    r = s[i]
    j = 0
    while j < len(s):
        g = s2[j]
        j = j + 1
        rows.append(g*base+r)
    i = i + 1
i = 0
s = shuffle(rBase)
s2 = shuffle(rBase)
while i < len(s):
    c = s[i]
    j = 0
    while j < len(s):
        g = s2[j]
        cols.append(g*base+c)
        j += 1
    i += 1
nums = shuffle(range(1,side+1))    
i =0
while i < len(rows):
    r = rows[i]
    j = 0
    while j < len(cols):
        c = cols[j]
        data.append(nums[pattern(r,c)])
        j += 1
    i += 1
print(rows)
print(cols)
print(data)

在Python中将“ for循环”转换为“ while循环”

1 个答案: