我正在尝试对值进行排序,但没有得到理想的结果。你能帮我怎么做吗?
示例:
df = pd.read_csv("D:/Users/SPate233/Downloads/iMedical/sqoop/New folder/metadata_file_imedical.txt", delimiter='~')
#df.sort_values(by = ['dependency'], inplace = True)
df.sort_values('dependency', ascending=True, inplace=True)
print(list(df['dependency'].unique()))
输出:
['0', '1', '1,10,11,26,28,55', '1,26,28', '10', '11', '12', '17,42', '2', '26,28', '33', '42', '6']
理想的输出:
['0', '1', '2', '6', '10', '11', '12', '33', '42', '17,42', '26,28', '1,26,28', '1,10,11,26,28,55']
答案 0 :(得分:2)
按字符串的长度,然后按其值排序:
df.assign(len = df.dependency.str.len()).sort_values(["len", "dependency"])
输出为(为清楚起见,保留了len
列):
dependency len
0 0 1
1 1 1
8 2 1
12 6 1
4 10 2
5 11 2
6 12 2
10 33 2
11 42 2
7 17,42 5
9 26,28 5
3 1,26,28 7
2 1,10,11,26,28,55 16