使用Wordpress中的当前帖子ID获取下一个/上一个帖子ID

时间:2011-06-12 20:21:51

标签: php jquery ajax wordpress fancybox

我想编写一个自定义的next / prev函数,以便在fancybox弹出窗口中动态显示帖子信息。因此,我需要使用PHP来根据Post当前显示的内容获取下一个和之前的帖子ID。我知道当前的帖子ID是什么,我可以将其发送到函数ok,但我无法弄清楚如何使用该ID来获取相邻的ID。

编辑:这是我到目前为止的代码(不起作用)

<?php
require_once("../../../wp-blog-header.php");

if (isset($_POST['data'])){
    $post_id = $_POST['data'];
}else{
    $post_id = "";
}
$wp_query->is_single = true;
$this_post = get_post($post_id);
$in_same_cat = false;
$excluded_categories = '';
$previous = false;
$next_post = get_adjacent_post($in_same_cat,$excluded_categories,$previous);


$post_id = $next_post->id;
$title = $next_post->post_title;

$dataset = array ( "postid"=>$post_id, "posttitle"=>$title );

//Because we want to use json, we have to place things in an array and encode it for json.
//This will give us a nice javascript object on the front side.

echo json_encode($dataset);


?>

3 个答案:

答案 0 :(得分:7)

get_adjacent_post()使用全局$post作为参考点,因此您需要替换它:

$this_post = get_post($post_id);

用这个:

global $post;
$post = get_post($post_id);

WordPress还提供get_next_post()get_previous_post(),您可以在此处使用,而不是将get_adjacent_post()与所有这些参数一起使用。这是最终产品:

<?php
require_once("../../../wp-blog-header.php");

if (isset($_POST['data'])){
    $post_id = $_POST['data'];
}else{
    $post_id = "";
}
$wp_query->is_single = true;

global $post;
$post = get_post($post_id);

$previous_post = get_previous_post();
$next_post = get_next_post();

$post_id = $next_post->id;
$title = $next_post->post_title;

$dataset = array ( "postid"=>$post_id, "posttitle"=>$title );

//Because we want to use json, we have to place things in an array and encode it for json.
//This will give us a nice javascript object on the front side.

echo json_encode($dataset);

?>

我不确定您希望将哪些密钥用于$dataset数组中上一个和下一个帖子的ID和标题,因此我暂时将其保留原样。

答案 1 :(得分:3)

要实现这一点,我必须将$next_post->id;更改为$next_post->ID;,即大写ID

我在index.php上的Wordpress中使用它 - 我将它插入循环的顶部:

<div class="work-post" id="<?php the_ID(); ?>">

然后在循环中我用这个: `             

        if (isset($_POST['data'])){
            $post_id = $_POST['data'];
        }else{
            $post_id = "";
        }
        $wp_query->is_single = true;

        global $post;
        $post = get_post($post_id);

        $next_post = get_next_post();
        $previous_post = get_previous_post();

        ?>

        <!-- call only if a value exists -->
            <?php if($next_post) : ?>
                <a href="#<?php echo $next_post->ID;?>" class="anchorLink"><div>PREV.</div></a>
            <?php endif; ?>
        <!-- call only if a value exists -->

        <!-- call only if a value exists -->
            <?php if($previous_post) : ?>
                <a href="#<?php echo $previous_post->ID;?>" class="anchorLink"><div>NEXT</div></a>
            <?php endif; ?>
        <!-- call only if a value exists -->`

答案 2 :(得分:2)

这是我的代码,它运作良好。 $ post_id是当前的帖子ID。

function get_previous_post_id( $post_id ) {
    // Get a global post reference since get_adjacent_post() references it
    global $post;
    // Store the existing post object for later so we don't lose it
    $oldGlobal = $post;
    // Get the post object for the specified post and place it in the global variable
    $post = get_post( $post_id );
    // Get the post object for the previous post
    $previous_post = get_previous_post();
    // Reset our global object
    $post = $oldGlobal;
    if ( '' == $previous_post ) 
        return 0;
    return $previous_post->ID; 
} 

function get_next_post_id( $post_id ) {
    // Get a global post reference since get_adjacent_post() references it
    global $post;
    // Store the existing post object for later so we don't lose it
    $oldGlobal = $post;
    // Get the post object for the specified post and place it in the global variable
    $post = get_post( $post_id );
    // Get the post object for the next post
    $next_post = get_next_post();
    // Reset our global object
    $post = $oldGlobal;
    if ( '' == $next_post ) 
        return 0;
    return $next_post->ID; 
} 

然后你只需要调用函数。例如:

echo get_previous_post_id( $current_id );
echo get_next_post_id( $current_id );
祝你好运!