Question

这是我正在处理的代码，我不知道为什么每次刷新页面时都需要单击2次以打开菜单。一旦我第二次单击全部正常。这是按钮的html：

var x = document.getElementById("overlay-menu");
x.style.height = "0%";

function showMenu() {
  var x = document.getElementById("overlay-menu");
  if (x.style.height === "0%") {
    x.style.height = "100%";
  } else {
    x.style.height = "0%";
  }
}

.overlay-menu {
  width: 100%;
  height: 0%;
  padding: 0;
  margin: 0;
  background-color: #ffffff;
  z-index: 10000;
  position: fixed;
  color: #0A0A0A;
  overflow: hidden;
  display: block;
  transition: .5s cubic-bezier(.55, .03, .26, 1.01);
}

.nav-menu-text {
  width: fit-content;
  height: fit-content;
  margin: 0;
  padding: 0;
  color: #EB761D;
  font-size: 15px;
  position: relative;
  top: 2.8em;
  cursor: pointer;
}

<p class="nav-menu-text" onclick="showMenu()">MENU</p>

<div class="overlay-menu" id="overlay-menu">
  <!-- code of the menu -->
</div>

Answer 1

x.style.height在代码运行时可能不是“ 0％”，请尝试从以下条件更改条件：

if (x.style.height === "0%") {

到

if (x.style.height !== "100%") {

为什么我必须单击2次才能运行此功能？

1 个答案: