Question

我正在努力解决部分完成的同事给我的查询。我得到的错误是“不是单组分组函数”，我尝试了各种分组依据语句，似乎都没有一个能解决我的问题

“未调整的其他”和“其他调整的”似乎是select语句中仅有的非聚合部分，但是当我尝试按那些分组时，似乎不起作用。

我还没有使用串联聚合字段的经验，因此我处于新领域，还无法对其进行故障排除。

SELECT CASE WHEN sum(unadj_gross_for_other_brand+adjustments_for_other_brand) = 0 AND
                 sum(adjustments_for_other_brand+redist_gross) = 0 THEN 0 ELSE 1 END status,
       'Unadjusted Other='||unadj_gross_for_other_brand||
       ' Adjustments Other='||adjustments_for_other_brand||
       ' Adjusted Other='||sum(unadj_gross_for_other_brand+adjustments_for_other_brand) ||
       ' Redistributed='||sum(redist_gross) Note
FROM
(
select
1 as unadj_gross_for_other_brand,
0 as adjustments_for_other_brand,
0 as redist_gross
from dual
UNION
select
0 as unadj_gross_for_other_brand,
2 as adjustments_for_other_brand,
0 as redist_gross
from dual
UNION
select
0 as unadj_gross_for_other_brand,
0 as adjustments_for_other_brand,
3 as redist_gross
from dual
);

预期结果如下：

Status    Note   
1         Unadjusted Other = 1, Adjusted Other = 2, Adjusted Other = 3, Redistributed = 3

或

Status    Note   
0         Unadjusted Other = 0, Adjusted Other = 0, Adjusted Other = 0, Redistributed = 0

Answer 1

您有对相同值的汇总和非汇总引用的混合。串联不是真的相关；如果将所有“注释”值都作为单独的列，则会遇到相同的问题。

由于只需要一行输出，因此只需将“注释”列中的前两个引用相加即可，

       'Unadjusted Other='||unadj_gross_for_other_brand||
       ' Adjustments Other='||adjustments_for_other_brand||

到

       'Unadjusted Other='||sum(unadj_gross_for_other_brand)||
----------------------------^^^^                           ^
       ' Adjustments Other='||sum(adjustments_for_other_brand)||
------------------------------^^^^                           ^

或原位：

SELECT CASE WHEN sum(unadj_gross_for_other_brand+adjustments_for_other_brand) = 0 AND
                 sum(adjustments_for_other_brand+redist_gross) = 0 THEN 0 ELSE 1 END status,
       'Unadjusted Other='||sum(unadj_gross_for_other_brand)||
       ' Adjustments Other='||sum(adjustments_for_other_brand)||
       ' Adjusted Other='||sum(unadj_gross_for_other_brand+adjustments_for_other_brand) ||
       ' Redistributed='||sum(redist_gross) Note
FROM (
...
);

    STATUS NOTE                                                                                                                                                                                                                               
---------- -----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
         1 Unadjusted Other=1 Adjustments Other=2 Adjusted Other=3 Redistributed=3

结果中的所有非文字值现在都是合计的，因此您不需要group-by子句。

db<>fiddle，其中两个版本的状态为零。

Answer 2

以下应该可以工作

SELECT CASE WHEN sum(unadj_gross_for_other_brand+adjustments_for_other_brand) = 0 
             AND sum(adjustments_for_other_brand+redist_gross) = 0 THEN 0 ELSE 1 
       END status
       ,'Unadjusted Other='||sum(unadj_gross_for_other_brand)
          ||' Adjustments Other='||sum(adjustments_for_other_brand)
          ||' Adjusted Other='||sum(unadj_gross_for_other_brand+adjustments_for_other_brand) 
          ||' Redistributed='||sum(redist_gross) as Note
  FROM (
        select
                1 as unadj_gross_for_other_brand,
                0 as adjustments_for_other_brand,
                0 as redist_gross
          from dual
        UNION
        select
                0 as unadj_gross_for_other_brand,
                2 as adjustments_for_other_brand,
                0 as redist_gross
          from dual
        UNION
        select
                0 as unadj_gross_for_other_brand,
                0 as adjustments_for_other_brand,
                3 as redist_gross
          from dual
        );

https://dbfiddle.uk/?rdbms=oracle_11.2

按语句分组，汇总和合并的案例语句？

2 个答案: