Question

我正在为纸牌游戏创建一个简单的计分员。得分最低的人获胜。我在字典中保留球员和得分：

players = {'bob': [3,6,4,3,7,3,6], 'joe': [3,7,5,9,9,7,8]}

我可以通过以下方式总结每个玩家的积分：

for player, score in players.items():
        print(f"\n{player.title()}'s final score is {sum(score)}")

现在，我想宣布获胜者（得分最低的人），但我无法使其工作。这是我尝试过的：

for points in players.values():
    score = sum(points)
winner = min(score)
print(f"The winner is {winner}!")

感谢您的帮助！

Answer 1

尝试一下

winner=min(players, key=lambda p:sum(players[p]))

Answer 2

print('The winner is {}'.format(min(players, key=lambda k: sum(players[k]))))

Answer 3

首先声明一个大数字，一个空的获胜者变量

创建一个dictionary语句，该语句打印所有point = 1000000; winner = '' for name,points in players.items(): temp = sum(points) #sum of all the num in the list if point > temp: # if point is > than the sum of the list replace the value of points point = temp winner = name print(f"The winner is {winner}!")值的名称和点

xterm control sequences

Python-在字典中找到列表的总和，然后找到值最低的列表

3 个答案: