Question

我有两个数据集，并且一直试图将它们组合在一起，但是不知道从哪里开始。我正在进行两个API调用，以下是响应的一个小示例：

{
    early_game_items: {
        57: 16
        59: 60
        106: 1
        180: 54
        214: 28
        232: 6
    },
    late_game_items: {
        108: 1
        116: 1
    },
    mid_game_items: {
        1: 52
        102: 3
        108: 4
        116: 1
        193: 1
        194: 1
        223: 1
        232: 73
    }
}

另一个数据集的编号范围为1-300ish，是由其他对象组成的对象。下面是一个代码段：

const items = [{
            "id": 57,
            "name": "void_stone",
            "cost": 825,
            "secret_shop": 1,
            "side_shop": 0,
            "recipe": 0,
            "localized_name": "Void Stone"
        },
        {
            "id": 58,
            "name": "mystic_staff",
            "cost": 2700,
            "secret_shop": 1,
            "side_shop": 0,
            "recipe": 0,
            "localized_name": "Mystic Staff"
        },
        {
            "id": 59,
            "name": "energy_booster",
            "cost": 900,
            "secret_shop": 1,
            "side_shop": 0,
            "recipe": 0,
            "localized_name": "Energy Booster"
        }...]

我需要通过将第一个数据集中的键与第二个数据集中的ID匹配，将第二个数据集中的数据放入第一个数据集中。例如：

{
    early_game_items: {
        57:  {amount: 16, name: 'void_stone', cost: 825}
        59:  {amount: 60...
        106: {amount: 1...
        180: {amount: 54...
        214: {amount: 28...
        232: {amount: 6...
    }...

非常感谢您关注此内容！我是JS的新手，并且真的在尝试学习。

Answer 1

命名数据集dataset1和dataset2，并假设dataset2是对象数组：

let result = {};

// key = 'early_game_items', 'mid_game_items', 'late_game_items'
for(let key in dataset1) {
    const itemGroup = dataset1[key];
    let _itemGroup = {}; 

    for(let id in itemGroup) {
        let _item = { amount: itemGroup[id] };
        // find item by id, in second dataset
        const item = dataset2.find(i => i.id == id) || {};
        // get name & cost via destructuring
        const { name, cost } = item;
        
        _item.name = name;
        _item.cost = cost;
        // store in new itemGroup
        _itemGroup[id] = _item;
    }
    // store in result
    result[key] = _itemGroup
}

console.log(result);

如果dataset2是一个以数字作为键的对象，则需要修改“按ID查找”功能：

// find item by id, in second dataset
const item = Object.values(dataset2).find(i => i.id === id) || {};

Answer 2

例如另一个答案，命名数据集dataset1和dataset2，并假设dataset2是对象数组。如果dataset2是大数组，则此答案具有更好的性能：

let result = {};
// key = 'early_game_items', 'mid_game_items', 'late_game_items'
for(let key in dataset1) {
    result[key] = {}; 
    for(let id in dataset1[key]) {
        result[key][id] = { amount: dataset1[key][id] };
    }
}
for(let id in dataset2) {
   for(let key in dataset1) {
      let _item;
      if(_item=result[key][id]){
         const { name, cost } = dataset2[id];
         _item.name = name;
         _item.cost = cost;
      }
   }
}
console.log(result);

尝试合并对象键ID匹配的两个数据集

2 个答案: