Question

你好，我有以下数据结构：

[
  {
    "name": "a name",
    "project": [
      {
        companyName: "a name",
        contactPerson: [
          {
            work_email: "test@test.com"
          }
        ]
      },
      {
        companyName: "a name1",
        contactPerson: [
          {
            work_email: "test1@test.com"
          }
        ]
      },
      {
        companyName: "a name2",
        contactPerson: [
          {
            work_email: "test2@test.com"
          }
        ]
      },
      {
        companyName: "a name3",
        contactPerson: [
          {
            work_email: "test@test.com"
          }
        ]
      },
      
    ]
  }
]

通过此查询，我想找到所有带有电子邮件test@test.com的项目：

db.collection.find({
  "project.contactPerson.work_email": "test@test.com"
},
{
  "project.$": 1
})

它仅返回找到的第一个结果，然后停止。但是在我的数据中，我有两个带有该电子邮件的项目，我想找到两个项目。如果可以的话，这是一个游乐场，您可以用来进一步帮助我。在此先感谢您，并非常感谢：https://mongoplayground.net/p/4Mpp7kHi98u

Answer 1

位置$运算符将an的内容限制为返回以下任意一个：

与数组中查询条件匹配的第一个元素。
如果没有为数组指定查询条件，则为第一个元素（从MongoDB 4.4开始）。 Ref

您可以执行以下操作

# filter out Group B and add a column with desire colour vector
m <- df %>% 
  select(Group, Proband.ID) %>% 
  filter(Group Group == "B") %>% 
  unique() %>% 
  mutate(cols = col_vector[1:17]) 

#filter out group A
s <- t %>% 
  select(Group, Proband.ID) %>% 
  filter(Group == "A") %>% 
  unique() 

# make a list containing the colour vector from `m` data frame and add empty strings to the size of "A" Proband's
mm <- list(prob = c(m$cols, (rep("",length(s$Proband.ID)))))

# name the list by concatenating in order and use this list in pheatmap annotatioin
names(mm$prob) <- c(as.character(m$Proband.ID), as.character(s$Proband.ID))

工作Mongo playground

Answer 2

db.collection.aggregate([
  {
    $unwind: "$project"
  },
  {
    $match: {
      "project.contactPerson.work_email": "test@test.com"
    }
  },
  {
    "$group": {
      "_id": "$_id",
      "name": {
        "$first": "$name"
      },
      "project": {
        "$push": {
          "companyName": "$project.companyName",
          "contactPersion": "$project.contactPerson"
        }
      }
    }
  }
])

Answer 3

// step1（与问题语句相关的查找）：，即使联系人的数组元素之一匹配，查找也显示所有项目，使用聚合函数显示特定的电子邮件ID

> db.test3.find({    "project.contact.email": "abc2@email.com" }).pretty();
{
        "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"),
        "name" : "Pega Contractors",
        "project" : [
                {
                        "pname" : "pname1",
                        "contact" : [
                                {
                                        "email" : "xyz1@email.com"
                                }
                        ]
                },
                {
                        "pname" : "pname2",
                        "contact" : [
                                {
                                        "email" : "abc2@email.com"
                                }
                        ]
                },
                {
                        "pname" : "pname3",
                        "contact" : [
                                {
                                        "email" : "xyz1@email.com"
                                }
                        ]
                }
        ]
}
--
//aggregate option:

//Step1: data preparation
> db.test3.find().pretty();
{
        "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"),
        "name" : "Pega Contractors",
        "project" : [
                {
                        "pname" : "pname1",
                        "contact" : [
                                {
                                        "email" : "xyz1@email.com"
                                }
                        ]
                },
                {
                        "pname" : "pname2",
                        "contact" : [
                                {
                                        "email" : "abc2@email.com"
                                }
                        ]
                },
                {
                        "pname" : "pname3",
                        "contact" : [
                                {
                                        "email" : "xyz1@email.com"
                                }
                        ]
                }
        ]
}
>

//step2: aggregate and unwind project for the next step pipeline input
> db.test3.aggregate([ {$unwind: "$project"}]);
{ "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"), "name" : "Pega Contractors", "project" : { "pname" : "pname1", "contact" : [ { "email" : "xyz1@email.com" } ] } }
{ "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"), "name" : "Pega Contractors", "project" : { "pname" : "pname2", "contact" : [ { "email" : "abc2@email.com" } ] } }
{ "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"), "name" : "Pega Contractors", "project" : { "pname" : "pname3", "contact" : [ { "email" : "xyz1@email.com" } ] } }

//step3: Desired outcome, i.e display data specific to email
> db.test3.aggregate([
...    {$unwind: "$project"},
...    {$match: {"project.contact.email":"xyz1@email.com"}}
...    ]);
{ "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"), "name" : "Pega Contractors", "project" : { "pname" : "pname1", "contact" : [ { "email" : "xyz1@email.com" } ] } }
{ "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"), "name" : "Pega Contractors", "project" : { "pname" : "pname3", "contact" : [ { "email" : "xyz1@email.com" } ] } }
> db.test3.aggregate([    {$unwind: "$project"},    {$match: {"project.contact.email":"acb2@email.com"}}    ]);
> db.test3.aggregate([    {$unwind: "$project"},    {$match: {"project.contact.email":"abc2@email.com"}}    ]);
{ "_id" : ObjectId("5f43fdc153e34ac6967fe8ce"), "name" : "Pega Contractors", "project" : { "pname" : "pname2", "contact" : [ { "email" : "abc2@email.com" } ] } }
>

Mongo查找查询仅返回一个结果

3 个答案: