如何在不使用集合的情况下在Python的两个字典值列表中找到公共元素？

Question

dmarks={'A': [100,127, 130, 123, 210], 'B': [127, 130, 123, 210, 109]}

Answer 1

如果您不能使用集合，我建议遍历列表。

dmarks={'A': [100,127, 130, 123, 210], 'B': [127, 130, 123, 210, 109,]}


def find_common(a,b): 
    return [value for value in a if value in b] 

results = find_common(dmarks['A'], dmarks['B'])
print(results)

Answer 2

检查是否有帮助：

dmarks={'A': [100,127, 130, 123, 210], 'B': [127, 130, 123, 210, 109]}
a,b,c=dmarks['A'],dmarks['B'],[]
for i in a:
    if i in b:
        c.append(i)
print(c)

Answer 3

尝试：

res = [a for a in dmarks['A'] if (a in dmarks['A']) and (a in dmarks['B'])]

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# [127, 130, 123, 210]