Question

假设我有一个类似'there goes "something here", and "here" and I have "nothing else to say"'的字符串。我需要一个正则表达式来准确检索['something here', 'here', 'nothing else to say']。请注意，结果不是用引号引起来的，这是因为我不想在每次比赛中再次致电replace(/"/g, '')。

作为参考，

'there goes "something here", and "here" and I have "nothing else to say"'.match(/".*?"/g)

给我这个：

['"something here"', '"here"', '"nothing else to say"']

但是，就像我说的那样，我不希望结果用引号引起来，并对每个结果进行replace调用。

Answer 1

这应该有效 "([^"]*)"
这是一个示例测试： https://regex101.com/r/CjK2fp/1

Answer 2

何时在第一个引号后加上\w：

string = 'there goes "something here", and "here" and I have "nothing else to say"';
regexp = /(?<=")\w.*?(?=")/g
result = string.match(regexp);
console.log(result);

请注意引号和内容之间应留有间隔：

let string = 'there goes " something here ", and "here" and I have "nothing else to say"';

function everyOther(string) {

let regexp = /(?<=").*?(?=")/g

let answerArray = [];

for (; ; ) {
    if (regexp.lastIndex !== 0) {
        regexp.lastIndex += 2;
    }
    let matchArr = regexp.exec(string);
    if (regexp.lastIndex === 0) { 
        break;
    } 
    let match = matchArr[0]
    answerArray.push(match);
}

console.log(answerArray);

}

everyOther(string);

Answer 3

通过使用一些最新的JS功能

let reg = /"(.*?)"/gi;
let results = str.matchAll(reg);

// results - is not an array, but an iterable object
// convert results to an Array
results =  Array.from(results); 

// using map method to get second items from each array item
// which is a captured group
results = results.map(item => item[1]);

更多信息=> javascript.info ::: matchAll with groups

从字符串中提取双引号的字符串，不带引号本身

3 个答案: