Question

我想在字符串中匹配单词的10个单词之前和之后打印。

例如，我有

SELECT * 
FROM 
    (
        SELECT FACULTY, YEAR, ADMINISSION, DROPPUTS 
        FROM TABLE
        PIVOT (SUM (ADMISSIONS) 
        FOR YEAR IN (2018,2019,2020)
    )

在上面的字符串中，我想搜索字母经验并想要类似的输出

string = "About the company -Our client is one of the world's fastest-growing AI-based contract management solution providers.Exp -7+ Years Location -MumbaiJob Role -Min 7years hands-on experience in Natural Language Processing, Machine Learning, Artificial Intelligence, and IBM Watson"

我尝试了Location -MumbaiJob Role -Min 7years hands-on experience in Natural Language"，但它只在单词之前返回一个。

Answer 1

在一个或多个空白字符上拆分单词可能是最好的方法：

import re

s = "About the company -Our client is one of the world's fastest-growing AI-based contract management solution providers.Exp -7+ Years Location -MumbaiJob Role -Min 7years hands-on experience in Natural Language Processing, Machine Learning, Artificial Intelligence, and IBM Watson"

words = re.split(r'\s+', s)
try:
    index = words.index('experience')
except Exception:
    pass
else:
    start = max(index - 5, 0)
    end = min(index + 6, len(words))
    print(' '.join(words[start:end]))

打印：

-MumbaiJob Role -Min 7years hands-on experience in Natural Language Processing, Machine

但是，如果您不愿意使用正则表达式，则应该在“体验”之前最多打印5个单词，在其后最多打印5个单词：

import re

s = "About the company -Our client is one of the world's fastest-growing AI-based contract management solution providers.Exp -7+ Years Location -MumbaiJob Role -Min 7years hands-on experience in Natural Language Processing, Machine Learning, Artificial Intelligence, and IBM Watson"

m = re.search(r'([\w,;!.+-]+\s+){0,5}experience(\s+[\w,;!.+-]+){0,5}', s)
if m:
    print(m[0])

打印：

-MumbaiJob Role -Min 7years hands-on experience in Natural Language Processing, Machine

更新为处理“体验”或“体验”

我还简化了正则表达式：

import re

s = "About the company -Our client is one of the world's fastest-growing AI-based contract management solution providers.Exp -7+ Years Location -MumbaiJob Role -Min 7years hands-on Experience in Natural Language Processing, Machine Learning, Artificial Intelligence, and IBM Watson"

# By splitting on one or more whitespace characters:
words = re.split(r'\s+', s)
try:
    index = words.index('experience')
except Exception:
    try:
        index = words.index('Experience')
    except Exception:
        index = None
if index:
    start = max(index - 5, 0)
    end = min(index + 6, len(words))
    print(' '.join(words[start:end]))


# Using a regular expression:
m = re.search(r'(\S+\s+){0,5}[eE]xperience(\s+\S+){0,5}', s)
if m:
    print(m[0])

打印：

-MumbaiJob Role -Min 7years hands-on Experience in Natural Language Processing, Machine
-MumbaiJob Role -Min 7years hands-on Experience in Natural Language Processing, Machine

Answer 2

您可以先用空格分隔单词，然后从前10个单词中选择单词，直到列表结尾，最后将列表分组以重做字符串

 ts=string.split(' ')[10:]
 print(" ".join(ts))

Answer 3

请在正则表达式下面尝试

((?:\S+\s){10})(experience)((?:\s\S+){10})

\1之前的10个单词，\3之后的10个单词

Demo

正则表达式中的前瞻性

3 个答案: