我一直在用Unity 3D开发游戏,其中涉及能够拾取一些物体。我当前的代码如下:
using System.Collections;
using System.Collections.Generic; 使用UnityEngine;
public class pickUp : MonoBehaviour
{
public Transform dest;
void OnMouseDown() {
GetComponent<Rigidbody>().useGravity = false;
GetComponent<Rigidbody>().velocity = new Vector3(0f, 0f, 0f);
GetComponent<Rigidbody>().angularVelocity = new Vector3(0f, 0f, 0f);
this.transform.position = dest.position;
this.transform.parent = GameObject.Find("Destination").transform;
}
void OnMouseUp() {
this.transform.parent = null;
GetComponent<Rigidbody>().useGravity = true;
}
void Update() {
//where I need to detect mouseover
}
}
正如注释中所隐含的那样,我需要检测鼠标是否位于对象上方,否则,它将关闭所有其他对象的物理功能。我也无法对名称进行编程(因此使用Ray),因为已经有许多对象使用了该脚本。
谢谢!
编辑:旧版本的代码,放入当前版本
答案 0 :(得分:0)
我认为您缺少了一些东西,void OnMouseDown(),OnMouseOver(),OnMouseUp(),仅调用了附加了对撞器和脚本的特定对象,无论您使用相同的对象多少次都没有关系多个对象的脚本。这些方法与每个对象无关。
答案 1 :(得分:0)
您原来的问题代码看起来像这样
void Update()
{
if (Input.GetMouseButton(0))
{
void OnMouseOver()
{
//where I need to detect mouseover
}
}
}
几乎已经存在,但是将其声明为Update
内的嵌套方法当然没有任何意义!
您的脚本应该看起来像
public class pickUp : MonoBehaviour
{
public Transform dest;
// You should already set this via the Inspector
[SerializeField] private Rigidbody _rigidbody;
private void Awake()
{
// or as fallback get it ONCE
if(!_rigidbody) _rigidbody = GetComponent<Rigidbody>();
}
private void OnMouseDown()
{
_rigidbody.useGravity = false;
_rigidbody.velocity = Vector3.zero;
_rigidbody.angularVelocity = Vector3.zero;
transform.position = dest.position;
transform.parent = GameObject.Find("Destination").transform;
}
private void OnMouseUp()
{
transform.parent = null;
_rigidbody.useGravity = true;
}
// Called every frame while the mouse stays over this object
private void OnMouseOver()
{
if (Input.GetMouseButton(0))
{
// whatever shall happen every frame while mouse over and mouse button 0 stays pressed
}
}
}
或者,如果仅在鼠标进入并存在该对象时才需要做某事,而不要使用
private void OnMouseEnter()
{
}
private void OnMouseExit()
{
}