Question

所以我无法弄清楚为什么我的插入操作符不能用于我的列表类。我已经看了一会儿，我认为重载的语法是正确的。在这一点上不确定。关于它为什么不工作的任何提示？这是代码：

编辑：将一些代码更改为当前的代码。

对不起，现在问题是我无法打印任何东西，简单的打印和空行。

这是司机：

#include <iostream>
#include "polynomial.h"

using namespace std;

int main(){
Polynomial* poly = new Polynomial();    

poly->set_coefficient(3,2);

poly->set_coefficient(0,2);

poly->set_coefficient(3,1);

cout << "trying to print data" << endl;
cout << *poly << endl;    
return 0;   
}

这是标题：

#ifndef _POLYNOMIAL_H_
#define _POLYNOMIAL_H_

#include <iostream>

class Polynomial {

public:

struct PolyNode {
    int coefficient, degree;
    struct PolyNode* next;      
    PolyNode(int c, int d, PolyNode* n): coefficient(c),degree(d),next(n){}
};

PolyNode* firstTerm;
Polynomial(): firstTerm(0) {} 

struct PolyNode* get_first(){
    return firstTerm;
}


//makes the term with degree d have a coefficient of c
void set_coefficient(int c, int d);     

~Polynomial();  

friend std::ostream& operator<<(std::ostream& o, const Polynomial& p);          
};

#endif

以下是实施：

#include "polynomial.h"
#include <iostream>
#include <ostream>

using namespace std;

void Polynomial::set_coefficient(int c, int d){
PolyNode* start = firstTerm;
if(c != 0 && firstTerm == 0)    
    firstTerm = new PolyNode(c,d,NULL);
else{   
    cout << "Entered set_coefficient()" << endl;
    while(start->degree != d && start->next != NULL){
        cout << "Inside set_coefficient() while loop" << endl;          
        start = start->next;        
    }       
    if(c != 0 && start == 0)    
        start = new PolyNode(c,d,0);
    else if(c!= 0 && start != 0)
        start->coefficient = c;
    else if(c == 0){
        cout << "deleting a term" << endl;          
        delete start;
    }
}   
    cout << "Leaving set_coefficient()" << endl;
}

ostream& operator<<(ostream& o,const Polynomial& p){
Polynomial::PolyNode* start = p.firstTerm;  
for(unsigned int i = 0; start->next != 0; i++){
    o << "Term " << i << "'s coefficient is: " << start->coefficient << " degree is: " << start->degree << endl << flush;
    start = start->next;
}   
return o;
}

Answer 1

poly是一个指针，用于使用您需要说明的自定义operator <<

cout << *poly; // output the object pointed-to, not the pointer itself

您没有超载插入Polynomial*的含义。你也不应该尝试。

除此之外，您可能应该通过const引用接受对象，没有理由让流输出操作符更改对象。

重载＆lt;＆lt;插入操作符无法正常工作

1 个答案: