如何确定工资大于平均工资

Question

假设我有下表

id  name city   salary  dept 

我想选择所有大于平均工资的工资

Answer 1

尝试这样的事情：

SELECT salary WHERE salary > (SELECT AVG(salary) FROM *)

Answer 2

假设它是mysql，只有以下两个工作。 （我使用临时表，因此名称与你的不同）

select * from b  where ref > (select avg(ref) from b);
select * from b  having ref > (select avg(ref) from b);

这不是 - select * from b having ref > avg(ref);

我尝试了一些查询 -

mysql> select * from b;
+------+------------+------+
| id   | d2         | ref  |
+------+------------+------+
|  300 | 2010-12-12 |    3 |
|  300 | 2011-12-12 |    2 |
|  300 | 2012-12-12 |    1 |
|  400 | 2011-12-12 |    1 |
+------+------------+------+
4 rows in set (0.00 sec)

mysql> select * from b  having ref > avg(ref);
+------+------------+------+
| id   | d2         | ref  |
+------+------------+------+
|  300 | 2010-12-12 |    3 |
+------+------------+------+
1 row in set (0.00 sec)

mysql> select * from b  having ref > (select avg(ref) from b);
+------+------------+------+
| id   | d2         | ref  |
+------+------------+------+
|  300 | 2010-12-12 |    3 |
|  300 | 2011-12-12 |    2 |
+------+------------+------+
2 rows in set (0.02 sec)

mysql> select * from b  where ref > (select avg(ref) from b);
+------+------------+------+
| id   | d2         | ref  |
+------+------------+------+
|  300 | 2010-12-12 |    3 |
|  300 | 2011-12-12 |    2 |
+------+------------+------+
2 rows in set (0.00 sec)

mysql> select *,avg(ref) from b  having ref > avg(ref);
+------+------------+------+----------+
| id   | d2         | ref  | avg(ref) |
+------+------------+------+----------+
|  300 | 2010-12-12 |    3 |   1.7500 |
+------+------------+------+----------+
1 row in set (0.00 sec)

Answer 3

如果支持窗口聚合函数：

SELECT Salary
FROM (
  SELECT
    Salary,
    AVG(Salary) OVER () AS AvgSalary
  FROM atable
) s
WHERE Salary > AvgSalary

Answer 4

它非常简单，只需按照下面的简短命令使用

SELECT *FROM table_name WHERE salary > avg(select salary from table_name)

希望你知道： - ）

Answer 5

select empno,e.deptno,sal 
  from emp e, ( select deptno,avg(sal) avsal 
                  from emp 
              group by deptno
              ) a 
 where e.sal > a.avsal 
   and e.deptno = a.deptno;

Answer 6

如果表格的名称是员工（身份证，姓名，城市，工资）

select salary from Employee where salary > (select ava(salary) from employee)

Answer 7

假设emp是表的名称，其部门ID为dept_id

1. 查询结果显示所有员工的工资大于该部门平均工资的详细信息。 （部门智者）

（按部门分组）

select e1.* from emp e1  inner join (select avg(sal) avg_sal,dept_id from emp group by
dept_id) as e2 on e1.dept_id=e2.dept_id and e1.sal>e2.avg_sal

1. 查询结果显示所有员工的工资大于平均工资的详细信息。

   select * from emp where sal > (select avg(sal) from emp)
   

Answer 8

遵循将为您工作。

SELECT salary FROM table_name WHERE salary > (SELECT AVG(salary) FROM table_name);