Question

如果“学年”的值被更改，则不会出现404。我希望仅当'school_year'和'pk'在url中都具有正确的值时才显示数据。

例如如果您有数据（School_Year = 2020，pk = 33）当您输入网址https://190.0.1/190/190/33和https://190.0.1/190/whatthell/33时两者都是相同的结果。

但是，我只想在两个值都正确时才显示结果。

我真的不知道我的解释是否正确，谢谢。

view.py

class StudentDetail(DetailView,FormView):
        model = Student
        template_name = 'student/member.html'
        context_object_name = 'student'
        form_class = AddConsultation
    
        def get_context_data(self, **kwargs):
            context = super().get_context_data(**kwargs)
            context['pk'] = Student.objects.filter(pk=self.kwargs.get('pk'))
            return context

url.py

path('student/<school_year>/<pk>/', views.StudentDetail.as_view(), name='student_detail'),

html链接

<a href='{% url 'student_detail' student.school_year student.pk %}'>

models.py

class Student(models.Model):
    school_year = models.CharField(
        max_length=10,
        choices=SCHOOL_YEAR_CHOICES,
        default='2021N',
        verbose_name='school year'
    )
    ... etc

Answer 1

我将删除get_context_data并使用get_object覆盖get_object_or_404：

class StudentDetail(DetailView, FormClass):
    model = Student
    template_name = 'student/member.html'
    context_object_name = 'student'
    form_class = AddConsultation

    def get_object(self, queryset=None):
        return get_object_or_404(Student, pk=self.kwargs['pk'], school_year=self.kwargs['school_year'])

其他解决方案可能是：

class StudentDetail(DetailView, FormClass):
    model = Student
    template_name = 'student/member.html'
    context_object_name = 'student'
    form_class = AddConsultation
    slug_field = 'school_year'
    slug_url_kwarg = 'school_year'
    query_pk_and_slug = True

但是我发现第一个少了魔法：）

将pk的两个传递给url

1 个答案: