Question

freinds，

我正在使用以下代码在我的应用程序中显示mp4视频并面临以下问题

我在google和stackoverflow上看到了很多与此问题相关的帖子，但是每个人都给出了自己的建议并且没有共同的答案。

1）我无法在模拟器中看到视频 2）在不同的手机中，有时会播放大量的视频，大部分时间都会给出上述信息。

我的代码

VideoView myVideoView = (VideoView)findViewById(R.id.videoview);

      String viewSource ="http://dev.hpac.dev-site.org/sites/default/files/videos/about/mobile.mp4";

      myVideoView.setVideoURI(Uri.parse(viewSource));
      myVideoView.setMediaController(new MediaController(this));
      myVideoView.requestFocus();
      myVideoView.start();

任何人都指导我这个问题的解决方案是什么任何帮助将不胜感激。

Answer 1

试试此链接

http://r00tsecurity.org/forums/topic/12059-android-videoview-example/

http://www.helloandroid.com/tutorials/how-play-video-and-audio-android

Answer 2

您可以使用您的文件创建输出流并获取流的绝对路径，然后将路径放入视频视图

    private String getDataSource(String path) throws IOException {
    if (!URLUtil.isNetworkUrl(path)) {
        return path;
    } else {
        URL url = new URL(path);
        URLConnection cn = url.openConnection();
        cn.connect();
        InputStream stream = cn.getInputStream();
        if (stream == null)
            throw new RuntimeException("stream is null");
        File temp = File.createTempFile("mediaplayertmp", "dat");
        temp.deleteOnExit();
        String tempPath = temp.getAbsolutePath();
        @SuppressWarnings("resource")
        FileOutputStream out = new FileOutputStream(temp);
        byte buf[] = new byte[128];
        do {
            int numread = stream.read(buf);
            if (numread <= 0)
                break;
            out.write(buf, 0, numread);
        } while (true);
        try {
            stream.close();
        } catch (IOException ex) {
            Log.e(TAG, "error: " + ex.getMessage(), ex);
        }
        return tempPath;
    }
}

和

public void initVideo() {
    try {

        if (!mVideoView.isPlaying()) {

            if (url > playList.size() - 1) {
                url = 0;
            }
            String[] playurl = (playList.get(url)).split("\\.");
            String urlExtention = playurl[playurl.length - 1];

            if (urlExtention.equals("mp4")) {
                playVideo(playList.get(url));
            } else if (urlExtention.equals("jpg")
                    || urlExtention.equals("jpeg")) {

                Intent intentShedule = new Intent(Default_Player.this,
                        ImagePlayer.class);

                intentShedule.putExtra("imagePath", playList.get(url));
                intentShedule.putExtra("urlValue", url);
                intentShedule.putExtra("playlistType", playlistType);
                intentShedule.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION);
                startActivity(intentShedule);
                finish();
            } else {
                Intent intentShedule = new Intent(Default_Player.this,
                        WebContentView.class);

                intentShedule.putExtra("webPath", playList.get(url));
                intentShedule.putExtra("urlValue", url);
                intentShedule.putExtra("playlistType", playlistType);
                intentShedule.addFlags(Intent.FLAG_ACTIVITY_NO_ANIMATION);
                startActivity(intentShedule);
                finish();
            }

        }

        mVideoView.setOnErrorListener(new MediaPlayer.OnErrorListener() {

            @Override
            public boolean onError(MediaPlayer mp, int what, int extra) {
                System.out.println("set on error listner");

                //do somthing if alert this video can not be played

                return false;
            }
        });

        mVideoView
                .setOnCompletionListener(new MediaPlayer.OnCompletionListener() {

                    public void onCompletion(MediaPlayer vmp) {

                        playnew();
                    }
                });

    } catch (Exception e) {

    }

    // TODO Auto-generated method stub

}

如果警告此视频无法播放，请使用错误列表器

Answer 3

在eclipse模拟器视频中

没有显示来自网站（互联网）的链接。如果你想播放特定的视频。然后制作原始文件夹并提供以下路径

String path1 =“android.resource：// your package name /”+ R.raw.video name;

Uri uri = Uri.parse（path1）;
videoView.setVideoURI（URI）;

对不起，这个视频无法在videoview中播放？

3 个答案: