Question

x = input(" write a quadratic equation ")
x=(x.replace(" ",""))

我写这是为了删除输入中的所有空格，从而使索引编制变得容易

q = x.find("x")
w=int(q+1)

代码运行良好，但是代码中的索引取决于x的索引如果有人用一个不同的变量写了一个方程然后x 下面是完整的代码

x = input(" write a quadratic equation ")
print ("")
x=(x.replace(" ",""))

q = x.find("x")

w=int(q+1)

abc = x[0:q+1]
bcd = x[w+1:]

if (x[w]!="^") :
    y=abc + "^2" +bcd
    y=(y.replace(" ",""))
    print(y)
else: 
    print(x,end ="""
    
""")

A = int(x[:w-1])


e=x.rfind("x")


B=int(x[w+1:e])


C=int(x[e+1:])


r=(((-B) - ((B*B)-(4*A*C))**(1/2))/            ((2*A)))
t=(((-B) + ((B*B)-(4*A*C))**(1/2))/((2*A)))
print( "the roots are " ,r,"and" ,t)

如何使代码适用于所有字母有什么办法可以将输入中的字母更改为1字母，即x

Answer 1

我建议检查'abcdefghijklmnopqrstuvwxyz'中的每个字符，然后调用x.find(character)。如果返回-1，则该字符不存在。重复迭代直到找到一个字符，并假定该字符是要解决的变量。

equation = input("Write a quadratic equation: ")
print("")
equation = equation.replace(" ","")

alphabet = 'abcdefghijklmnopqrstuvwxyz'
index = -1
i = 0

while index == -1:
    index = equation.find(alphabet[i])
    i += 1

letter = equation[index]

# continue rest of program from here, assuming letter variable is the character to solve for

二次方程式求解器仅求解变量x的二次方程

1 个答案: