我想做的是记录一张看起来像这样的记录:
Start_DT End_DT ID
4/5/2013 4/9/2013 1
并将其更改为以下形式:
DT ID
4/5/2013 1
4/6/2013 1
4/7/2013 1
4/8/2013 1
4/9/2013 1
它可以用Python完成,但是我不确定SQL Oracle是否可以?我很难完成这项工作。任何帮助将不胜感激。
谢谢
答案 0 :(得分:1)
使用递归子查询分解子句:
WITH ranges ( start_dt, end_dt, id ) AS (
SELECT start_dt, end_dt, id
FROM table_name
UNION ALL
SELECT start_dt + INTERVAL '1' DAY, end_dt, id
FROM ranges
WHERE start_dt + INTERVAL '1' DAY <= end_dt
)
SELECT start_dt,
id
FROM ranges;
其中的示例数据:
CREATE TABLE table_name ( start_dt, end_dt, id ) AS
SELECT DATE '2013-04-05', DATE '2013-04-09', 1 FROM DUAL
输出:
START_DT | ID :------------------ | -: 2013-04-05 00:00:00 | 1 2013-04-06 00:00:00 | 1 2013-04-07 00:00:00 | 1 2013-04-08 00:00:00 | 1 2013-04-09 00:00:00 | 1
db <>提琴here
答案 1 :(得分:0)
按级别连接对于解决这些问题很有用。假设第一个名为“ table_DT ”的CTE是您的表名,因此您可以在此之后使用select语句。
with table_DT as (
select
to_date('4/5/2013','mm/dd/yyyy') as Start_DT,
to_date('4/9/2013', 'mm/dd/yyyy') as End_DT,
1 as ID
from dual
)
select
Start_DT + (level-1) as DT,
ID
from table_DT
connect by level <= End_DT - Start_DT +1
;