如何将列表转换成字典，其中第一个列表是键，第二个列表是字典中的值？

Question

我正在尝试关注问题

我竭尽所能，但被困在最后，将列表转换为上面给出的有问题的字典，即enter code here namespace App\Http\Controllers\Auth; use Socialite; use App\Http\Controllers\Controller; use App\Providers\RouteServiceProvider; use App\Models\User; use App\Models\socialProvider; use Illuminate\Foundation\Auth\RegistersUsers; use Illuminate\Support\Facades\Auth; use Illuminate\Support\Facades\Hash; use Illuminate\Support\Facades\Validator; //use Laravel\Socialite\Facades\Socialite; class RegisterController extends Controller 这是我如何解决上述问题的方法。

{1.3:[1.2,1.4]}

如何在最后将列表转换为字典？即{1.3：[1.2,1.4]}

Answer 1

检查此

lst=dict() # create an empty dictionary
l=[1.3]
k=[1.2,1.4,1.5,1.6,2.3,3.4,3.6,3.8,4.2,5.4,5.8]
for x in range(len(l)):
    lst[str(l[x])] = [] # create a new dict entry with a key from l and an empty list
    for z in range(len(k)):
        b=k[z]-l[x]
        if b>0.1:
            l.append(k[z])
        elif b<=0.1:
            print(lst[str(l[x])].append(k[z]))  # add to the empty list inside the dictionary of corresponding entry in l that you are checking with
print(lst)
print(l)

{'1.3': [1.2, 1.4]}
[1.3, 1.5, 1.6, 2.3, 3.4, 3.6, 3.8, 4.2, 5.4, 5.8]

Answer 2

我最终使用了fromkey()方法，它解决了我的问题

new_dict=[]
compare_value = 0.1
list_main=[1.3]
test_set=[1.2,1.4,1.5,1.7,2.3,3.4,3.6,3.8,4.2,5.4,5.8]
for x in range(len(list_main)):
   for z in range(len(test_set)):
       diff=test_set[z]-list_main[x]
       if diff>compare_value:
           list_main.append(test_set[z])
       elif diff<=compare_value:
           new_dict.append(test_set[z])
           dictionary=dict.fromkeys(list_main, new_dict)
print('dictionary----',dictionary)
print('list-------',list_main)