删除viewpager项目,而无需重新加载其他项目

时间:2020-10-21 05:15:16

标签: android android-viewpager

我使用FragmentPagerAdapter。当我从itemList中删除项目并notifyDataSetChanged.Fragments重新加载。在这种情况下,我正在丢失其他片段中的数据。如何在不丢失其他片段中数据的情况下实现这一目标

public class BasicViewPagerAdapter extends FragmentPagerAdapter {

private final List<Fragment> mFragments;

public BasicViewPagerAdapter(FragmentManager fm, List<Fragment> fragments) {
    super(fm);
    this.mFragments = fragments;
}

@Override
public Fragment getItem(int i) {
    return mFragments.get(i);
}


@Override
public int getCount() {
    return mFragments.size();
}


public void remove(int cashBoxPosition) {
    mFragments.remove(cashBoxPosition);
    notifyDataSetChanged();
}

}

fragmentList.remove(event.getCashBoxPosition()); mAdapterViewPager.remove(event.getCashBoxPosition());

2 个答案:

答案 0 :(得分:0)

通过onSaveInstanceState/onViewStateRestored在要保存数据的片段中保存并恢复状态,这是唯一的方法

答案 1 :(得分:0)

最后使用viewpager2解决了

public class BasicViewPager2Adapter extends FragmentStateAdapter {

private List<Fragment> mFragments;

public BasicViewPager2Adapter(FragmentActivity fa, List<Fragment> fragments) {
    super(fa);
    this.mFragments = fragments;
}

@NonNull
@Override
public Fragment createFragment(int i) {
    return mFragments.get(i);
}

@Override
public int getItemCount() {
    return mFragments.size();
}

@Override
public long getItemId(int position) {
    return mFragments.get(position).hashCode();
}

@Override
public boolean containsItem(long itemId) {
    return super.containsItem(itemId);
}

public void remove(int cashBoxPosition) {
    mFragments.remove(cashBoxPosition);
    notifyDataSetChanged();
}

}

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