查询问题

Question

我在尝试什么：

SELECT 
`update_photo`, 
(SELECT substring_index (`username`, ' ', 1)), 
`id_user`
FROM users 

JOIN worker_has_profession
ON worker_has_profession.worker_single_user_users_id_user  = users.id_user

ORDER BY `registration` 
DESC LIMIT 10

输出将是：

path photo | John | 31

但是我需要这样的东西（职业在另一张桌子里）

path photo | John | 31 | designer

表格

   <table worker_has_profession>
    worker_single_user_users_id_user //same id of id_user
    profession_id_profession 

      worker_single_user_users_id_user            profession_id_profession 
                    31                                      10


   <table profession>
    id_profession 
    profession

     id_profession               profession 
           10                      designer

有什么想法吗？

Answer 1

添加了以下联接和专业选择列表。

SELECT 
update_photo, 
(SELECT substring_index (`username`, ' ', 1)), 
U.id_user,
P.profession
FROM users U

JOIN worker_has_profession WP
ON WP.worker_single_user_users_id_user  = U.id_user

JOIN profession P
ON P.id_profession =  WP.profession_id_profession
ORDER BY registration
DESC LIMIT 10