Question

我正在用C＃编写一个读写SQLite的程序（System.Data.Sqlite）我有一个看起来像这样的表

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
1        1      10      1      2011-06-01 10:20:30.333
1        2      20      3      2011-06-01 10:20:30.444
2        1      100     11     2011-06-01 10:20:30.333
2        2      22      32     2011-06-01 10:20:30.444
1        1      20      2      2011-06-01 10:30:30.333
1        2      30      4      2011-06-01 10:30:30.444
2        1      22      22     2011-06-01 10:30:30.333
2        2      33      44     2011-06-01 10:30:30.444
1        1      10      1      2011-06-02 10:20:30.333
1        2      20      3      2011-06-02 10:20:30.444
2        1      11      11     2011-06-02 10:20:30.333
2        2      22      32     2011-06-02 10:20:30.444
1        1      20      2      2011-06-02 10:30:30.333
1        2      30      4      2011-06-02 10:30:30.444
2        1      22      22     2011-06-02 10:30:30.333
2        2      33      44     2011-06-02 10:30:30.444

我需要为每个用户提供三件事。

1）每个产品的最后一次输入，用于Value1和2，总计为两个值，即所有产品的总和。即对于2011-06-01的用户1，它将是Value1 = 50和Value2 = 6.

我实际上使用了：

SELECT * FROM TickData AS a,;
(SELECT USERID, DATE(TIME) AS JUSTDATE, MAX(TIME) AS MTIME;
FROM TickData;
GROUP BY 1,2;
) AS b;
WHERE a.USERID = b.USERID;
AND a.TIME = b.MTIME;
AND STRFTIME('%Y-%m',a.TIME) = STRFTIME('%Y-%m','NOW');
AND a.USERID = 1;

返回：

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
1        1      20      2      2011-06-01 10:30:30.333
1        2      30      4      2011-06-01 10:30:30.444

2011-06-01。然后我遍历数据并在日期相同时添加值。给我Value1 = 50和Value2 = 6.

2）所有产品的每天Value1的最高入口总额。即对于2011-06-01的用户2，它将是Value1 = 133。

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
2        1      100     11     2011-06-01 10:20:30.333
2        2      33      44     2011-06-01 10:30:30.444

3）所有产品的Value1每天的最低条目总计。即对于2011-06-01的用户2，它将是Value1 = 44。

UserID  ProdID  Value1  Value2  TIME
------------------------------------------------
2        2      22      32     2011-06-01 10:20:30.444
2        1      22      22     2011-06-01 10:30:30.333

我还没有运气2或3。

有没有人有任何吸烟

Answer 1

好好在周末完成自己的工作

1）

SELECT sum(value1), sum(value2) FROM TickData AS a,
(SELECT USERID, PRODID, DATE(TIME) AS JUSTDATE, MAX(TIME) AS MTIME
FROM TickData
GROUP BY 1,2,3
) AS b
WHERE a.USERID = b.USERID
AND a.TIME = b.MTIME
AND STRFTIME('%Y-%m',a.TIME) = STRFTIME('%Y-%m','NOW')
AND a.USERID = 1
GROUP BY JUSTDATE

2）

SELECT sum(Mval) FROM TickData AS a,
(SELECT USERID, PRODID, DATE(TIME) AS JUSTDATE,ID, MAX(value1) AS Mval
FROM TickData
GROUP BY 1,2,3
) AS b
WHERE a.USERID = b.USERID
AND a.ID = b.ID
AND STRFTIME('%Y-%m',a.TIME) = STRFTIME('%Y-%m','NOW')
AND a.USERID = 2
GROUP BY JUSTDATE

3）

SELECT sum(Mval) FROM TickData AS a,
(SELECT USERID, PRODID, DATE(TIME) AS JUSTDATE,ID, MIN(value1) AS Mval
FROM TickData
GROUP BY 1,2,3
) AS b
WHERE a.USERID = b.USERID
AND a.ID = b.ID
AND STRFTIME('%Y-%m',a.TIME) = STRFTIME('%Y-%m','NOW')
AND a.USERID = 2
GROUP BY JUSTDATE

编辑：可以使用一个查询完成2和3：

SELECT sum(Mval), sum(Mval2) FROM TickData AS a,
(SELECT USERID, PRODID, DATE(TIME) AS JUSTDATE,ID, MAX(PL) AS Mval,MIN(PL) AS Mval2
FROM TickData
GROUP BY 1,2,3
) AS b
WHERE a.USERID = b.USERID
AND a.TIME = b.MTIME
AND STRFTIME('%Y-%m',a.TIME) = STRFTIME('%Y-%m','NOW')
AND a.USERID = 2
GROUP BY JUSTDATE

获取每个日期的总和

1 个答案: