如何在单击iOS中的现有图像时更改图像?

时间:2020-10-28 11:29:47

标签: ios swift uitableview uiimageview

我在tableViewcell中有一个包含图像的按钮。我想获得在点击上一张图像(即一个按钮)时更改图像的选项,例如打开画廊或照相机。我正在使用以下代码来实现此目的: 在tableView单元格中:

protocol Profile2 : class{
    func OnClick_2(index : Int)
}
class TableViewCell: UITableViewCell {
   weak var celldelegate : Profile2?
    var index : IndexPath?
  }

在View Controller中

   @IBAction func changeProfileImage(_ sender: Any) {
 let action_sheet = UIAlertController(title: "Click to choose photo", message: nil, preferredStyle: .actionSheet)
               
               
               
               action_sheet.addAction(UIAlertAction(title: "Gallery", style: .default, handler: { (action) in
                   self.ShowAlbum()
               }))
               action_sheet.addAction(UIAlertAction(title: "Cancel", style: .cancel, handler: nil))
        }
//Show album method
func ShowAlbum()
       {
           let imagePicker = UIImagePickerController()
           imagePicker.delegate = self
           imagePicker.sourceType = .photoLibrary
           present(imagePicker, animated: true, completion: nil)
        imagePicker.allowsEditing = true
       }
//In cell for row method:
  cell.celldelegate = self
            cell.index = indexPath
            cell.profilePicture.isUserInteractionEnabled = true
//imagepicker method
   func imagePickerController(picker: UIImagePickerController!, didFinishPickingImage image: UIImage!, editingInfo: NSDictionary!){
           self.dismiss(animated: true, completion: { () -> Void in

           })
       let cell = tableView.dequeueReusableCell(withIdentifier: "profilePictureCell") as! TableViewCell
        cell.profilePicture.imageView?.image = image
        
       }

在点击按钮时会打开操作表,以便从图库中上传图像,但是在选择图像并进行上传时,按钮并没有设置。 请建议我如何解决或以其他方式解决。

0 个答案:

没有答案
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